Of course! Just study hard, exams are a big part of your grade most of the time! I also have exams
First, let's get the area of the entire triangle since we'll need it later. The area of a triangle is A=1/2*b*h
We can find the height with the Pythagorean theorem by splitting the triangle in half.
3^2+b^2=6^2
9+b^2=36
b^2=27
b=√27
Then we can find the area:
A=1/2*6*√27
A=3√27 or =9√3 or 15.59
Now we can find the area of each region in the triangle other than the shaded region because they are all portions of a circle.
Each region has an angle of 60 because this is an equilateral triangle. Therefore the area of each region other than the shaded region will be 1/6 the area of a circle with a radius of 3 because a full circle is 360 degrees.
A=pi*r^2/6
A=pi*9/6
A=4.71
So three of these regions would have an area of 14.14
We do the area of the triangle minus the area of these regions to get the area of the shaded region
15.59-14.14 = 1.45
Hope this helps!
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Answer:
b
c
Step-by-step explanation:
First question: x - 6 means there is a shift to the right.
Second Question: substitute the given values into the original equation for appropriate transformations.
Answer: 3 |x-4| + 2, because vertical stretch multiplies x, horizontal shifts are subtracted or added to x, and vertical shifts are added or subtracted to the entire function.
Here, A.P. is 3x-1, 4x, 5x+1, 4
i) Common difference (d)
(5x-1) - 4x = x - 1
It would be same as 4 - (5x-1) = 4-5x+1 = 5-5x
Now, x - 1 = 5 - 5x
5x + x = 5 + 1
6x = 6
x = 6/6
x = 1
So, Common difference would be 1
ii) Eight term will be: a + (n-1)d = 2 + (8-1)2 = 2+7(2) = 2+14 = 16
So, eight term would be 16
Hope this helps!
