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Len [333]
2 years ago
9

Ralph is three times as old is Sarah. In six years Ralph will be only twice as old as Sarah will be then. Find Ralphs age now. W

hich of the following equations can be used to solve the problem.
Mathematics
2 answers:
andrew11 [14]2 years ago
5 0
Let's begin by calling Sarah's age now as X. As Ralph is 3 times as old as Sarah, X times 3 = 3X. Hence, Ralph's age is 3X. In six years, Ralph will be twice as old as Sarah. To calculate six years from now, add 6 to X for Sarah, and 6 to 3X for Ralph. As Ralph is twice as old as Sarah and we want to find the difference between the ages to calculate X, multiply X+6 by 2. You'll get 2X+12. Therefore, 2X+12=3X+6. Deduct 6 from 3X+6 as we want to isolate the variable. Because you did that to one side, you have to deduct 6 from 2X+12. Hence, now you have 2X+6=3X. X=6. Ralph's age is 3X, so 6 times 3 is 18. Ralph is 18 years old. 
luda_lava [24]2 years ago
3 0

Answer:3x+6=2(x+6)

Step-by-step explanation:

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2 years ago
Which Value Is The Eighth Term In The Sequence? <br><br> A. -3125<br> B. -125<br> C. -625
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Answer:

C

Step-by-step explanation:

Substitute n = 8 into the explicit rule

a_{8} = - \frac{1}{125} × 5^{7}

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6 0
3 years ago
A rectangular garden has links twice as great as it's with a second rectangular garden has the same link as the first garden and
irinina [24]

Solution :

For the bigger rectangle

Width of bigger rectangle = W

Length of bigger rectangle, L = 2W

For the smaller rectangle

Width , w = W+4

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Now we know,

Area = length x width

$a=l \times w$

$120=(2W) \times (W+4)$

$120=2W^2 + 8W$

$2W^2+8W-120=0$

$W^2+4W-60=0$

$(W+10)(W-6) = 0$

We get, either W=-10   (rejecting)

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∴ length of the bigger rectangle, $L=2W $

                                                          = 2(6)

                                                           = 12 m

 Length of the smaller rectangle, $L=2W$

                                                            = 2(6)

                                                           = 12 m

Hence, the length of the two gardens is 12 m.                                                            

6 0
2 years ago
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timofeeve [1]

Answer:

See answer below.

Step-by-step explanation:

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3 0
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