Answer:
3(x + 9)(x + 2)x = 0
Step-by-step explanation:
xv1 = −9
xv2 = −2
xv3 = 0
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320
Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)
The integers are (x, y) = (40, 8).
Answer:
5x^2+2x-432
Step-by-step explanation:
15x^2+x-215×2+x−2
=15x^2+x-430+x−2
=15x^2+x+x-430-2
=15x^2+2x-432
Answer:
Solve for y, graph it, and then find where the lines intersect.You can take a table and put in all the x and y values. Then graph it. And see where it intersects. Because usually, these equations are lines
Answer: 0=0 The input is an identity or it is true for all values
-3(2x+6)=-6x-18
(-3*2x)+(-3*6)=-6x-18
-6x+-18=-6x-18
0=0
