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NARA [144]
3 years ago
6

Write an expression for the sequence of operations described below. multiply 3 by t, triple the result, then raise what you have

to the 8th power not simplify any part of the expression .
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer: 43046721(t^8)

Step-by-step explanation:

So first, multiply 3 by t to get 3t. Then, multiply it again by 3 to get 9t. Raise it to the 8th power to get (9^8)(t^8). This gives you 43046721(t^8)

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A bank exchanges United States currency for British courrency at the rate of 1.60 dollars to the £ .
kompoz [17]

Answer:

Remember that £ has a greater value compared to $ and vice versa.

5 0
3 years ago
What is the value of the expression <br> 7⋅(−5)⋅4?
Masja [62]
Multiply each number. Remember that when multiplying a negative and positive number, the outcome will be negative

7 x -5 = -35
-35 x 4 = -140

-140 is your answer

hope this helps
4 0
3 years ago
Read 2 more answers
Paul's mom, Gina, owns her home outright, without a mortgage. It is currently worth $100,000. If she could get five percent inte
Gala2k [10]
Use the formula   i = p*r*t.

Here, p = $100000, r = 0.05 and t = 1 (year)

The interest would be   i = $100000*0.05*1 = $5000 per year.
7 0
3 years ago
Read 2 more answers
Find the value of questions​
Zolol [24]

Answer:

The simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

Step-by-step explanation:

Given the expression

\frac{3^9\times \:y}{2\times 81}

solving the expression

\frac{3^9\times \:y}{2\times 81}=\frac{3^9y}{162}

        =\frac{3^9y}{3^4\times \:2}                ∵    162=3^4\times \:2      

        =\frac{3^5y}{2}                   ∵   \mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

       =\frac{243y}{2}                  ∵    3^5=243

Therefore, the simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

6 0
3 years ago
Ryan, a baker, measured the weights of cakes baked in each batch at his bakery and found that the mean weight of each cake is 50
denpristay [2]

Answer: Rejecting the mean weight of each cake as 500 gram when H subscript 0 equals 500

Step-by-step explanation:

Given that :

Null hypothesis : H0 =500

Alternative hypothesis : Ha < 500

Type 1 Error: Type 1 error simply occurs when we reject the Null hypothesis when the Null is true. Alternatively, type 11 error occurs when we fail to reject a false null hypothesis.

Hence, in the scenario above, a type 1 error will occur when we reject the mean weight as 500 even though the Null hypothesis is True.

6 0
4 years ago
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