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2 years ago

Tony can cycle a distance of 9 5/6 miles in 3/5 hours. What is his unit rate

Mathematics

1 answer:

Eva8 [605]2 years ago

3 0

Answer:

95/6

3/5

Step-by-step explanation:

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F(x) = (1) What is the x intercept

Vinvika [58]

Answer:

There is no x-intercept, only a y-intercept, which would be 1

8 0

3 years ago

Graph the set of points. Which model is most appropriate for the set?

Mila [183]

Answer:

A. quadratic

Step-by-step explanation:

the four points forms a curve that is parallel (parabola). quadratic is the shape of a curve like that

and exponential is only a curve

linear is like a straight line

4 0

3 years ago

Find the value of x when the triangle has 9 and 3

DENIUS [597]

Answer:

H²=h²+b²

H²=9²+3²

H²=81+9

H²=90

$\sqrt{90}$

5 0

2 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

B) Amount Rs 5760, Interest Rs 1526

Crazy boy [7]

Given :

Amount, A = 5760 Rs.

Interest in the amount, I = 1526 Rs.

To Find :

We need to find the % rate of interest.

Solution :

Let, us assume it is simple interest.

So,

$Interest = \dfrac{price \times rate \times time}{100}\\\\1526 = \dfrac{5760 \times r \times m}{100}\\\\r = \dfrac{152600}{5760m}\\\\r = \dfrac{26.5}{m}$

Hence, this is the required solution.

6 0

3 years ago