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3 years ago

1

Mathematics

1 answer:

Leto [7]3 years ago

5 0

I’m not even sure if that’s possible

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Part B: Write a polynomial expression that represents the total area of the swimming pool and walkway. To earn full credit, show

SVETLANKA909090 [29]

30x + 15x^2 - 1 I think not sure though

5 0

3 years ago

Read 2 more answers

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

What is the product of 1/2 and 3/5 ?

Svetradugi [14.3K]

Answer:

3/10

I think??

6 0

3 years ago

Read 2 more answers

Line m is parallel to line n. Name a pair of corresponding angles. A. 2 and 5 B. 3 and 6 C. 1 and 7 D. 3 and 7

Sauron [17]

Answer:

C. 1 and 7

Step-by-step explanation:

7 0

3 years ago

Do I set the equation up like this and then multiply the 2 on everything?

dybincka [34]

No no need to take out the 2
You can factor this by using the ac method

2x^2 + 3x - 5 = 0

multiplying the first and last coefficients 2 * -5 = -10
Now we want to get 2 factors of -10 which will give us +3 when added:-
+5 and -2 seem ok so we write:-

2x^2 - 2x + 5x - 5 = 0

2x(x - 1) + 5 (x - 1) =0

(2x + 5)(x - 1) = 0

Solution is x = -5/2 and x = 1

3 0

4 years ago