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alexandr402 [8]
3 years ago
8

Find the area of the shaped region

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

Answer: B

Step-by-step explanation:

A = 0/360 ×π×r^2

=135/360×π×11×11

=142.55 yd^2

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HOW DO I FIND QR<br><br> PLEASE HELP
Paul [167]

Solution: For finding QR we need to apply Pythagoras Theorem

What is Pythagoras Theorem ?

ans : Pythagoras Theorem is the sum of square of two sides which is equal to the third side or the hypotenuse. This formula is valid oy incase of Right-Angled Traingle because one of three angles here is 90°

According to this law let's apply it in the diagram shown here.

  • (Hypotenuse)² = (Adjacent)² + (Opposite)²

  • (PR)² = (QR)² + (PQ)²

  • (5x - 2)² = (QR)² + (3x - 1)²

  • (QR)² = (5x - 2)² - (3x - 1)²

After factorising both of them we get

  • (QR)² = 25x² - 20x + 4 - (9x² - 6x + 1)

  • (QR)² = 25x² - 20x + 4 - 9x² + 6x - 1

  • (QR)² = 16x² - 14x + 3

  • QR = √(16x² - 14x + 3)

So, QR is √(16x² - 14x + 3)

8 0
3 years ago
Triangles ABC and DEF are similar. Find the lengths of AB and EF. Right triangles A B C and D E F. Side A B is 5 x, side B C is
Doss [256]

Answer:

Ummm...

Step-by-step explanation:

7 0
2 years ago
What is the value of y in the equation 4(5y − 8 − 2) = 185 − 15? 8. 5 9. 7 10. 5 42. 5.
Bezzdna [24]

Answer:

10.5 is the answer

Step-by-step explanation:

4(5y−8−2)=185−15

(4)(5y)+(4)(−8)+(4)(−2)=185+−15(Distribute)

20y+−32+−8=185+−15

(20y)+(−32+−8)=(185+−15)(Combine Like Terms)

20y+−40=170

20y−40=170

20y−40+40=170+40

20y=210

20y/20=210/20

y=21/2

y=10.5

6 0
2 years ago
Gabriel has a stack of nickels that is 0.72 inch tall. The thickness of a nickel is 0.08 inch. How many nickels does Gabriel hav
olganol [36]
Gabriela has a stack of 9 nickels.
0.72 x 9 = 0.08
7 0
3 years ago
A plane averaged 800 mph on a trip going​ east, but only 400 mph on the return trip. The total flying time in both directions wa
galina1969 [7]

Answer:

1200 miles.

Step-by-step explanation:

Let d represent one way distance.

We have been given that a plane averaged 800 mph on a trip going​ east, but only 400 mph on the return trip.

\text{Time}=\frac{\text{Distance}}{\text{Speed}}

The time taken while going east would be \frac{d}{800}.

The time taken while returning back would be \frac{d}{400}.

Since the total flying time in both directions was 4.5 hr, so we will equate sum of both times with 4.5 as:

\frac{d}{800}+\frac{d}{400}=4.5

Make a common denominator:

\frac{d}{800}+\frac{d*2}{400*2}=4.5

\frac{d}{800}+\frac{2d}{800}=4.5

\frac{d+2d}{800}=4.5

\frac{3d}{800}=4.5

\frac{3d}{800}\times \frac{800}{3}=4.5\times \frac{800}{3}

d=1.5\times \frac{800}{1}

d=1200

Therefore, the one-way distance was 1200 miles.

5 0
3 years ago
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