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Natalija [7]
3 years ago
6

What is the ewuation of a line with a slope of 10 that goes theough the point (2,5)

Mathematics
1 answer:
den301095 [7]3 years ago
3 0
Use a graph
Answer: Y=10x-15
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What is the slope of a line that is perpendicular to the line y = x + 4? The slope of the line is ______?
serg [7]
Slopes of perpendicular lines are opposite reciprocals of each other. The slope of the given equation (which is in slope-intercept form) is 1, the invisible coefficient of x. The opposite reciprocal of 1 is -1, thus the slope of a line perpendicular to the line y = x + 4 is -1.

Hope this helps.
8 0
3 years ago
PLEASE HELP!
Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

\textrm{Slant height  l} = \sqrt{r^2 + h^2}  (1)

\textrm{Lateral surface area} = \pi r l

\textrm {Base area} = \pi r^2

\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l) (2)

\textrm{Volume V = } (1/3)  \pi r^2h (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA}  = 4\pi(4 + 8.944) =  4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04

Figure(b)

r = 7, h =15

\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55

\textrm{SA}  = 7\pi(7 + 16.55) =  517.89

Figure (c)

r = 5, l = 8

h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA}  = 5\pi(5 + 8) =  204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5


6 0
2 years ago
686.924 rounded to the nearest ten
bixtya [17]
690 because 86 is rounded up to 90
8 0
3 years ago
Read 2 more answers
which equation results from isolating a radical term and squaring both sides of the equation for the equation
damaskus [11]

Answer:

D) c - 2 = 25 + c + 10√c

Step-by-step explanation:

The given equation is \sqrt{c - 2} - \sqrt{c}  = 5

\sqrt{c -2} = 5 + \sqrt{c} \\

Taking square on both sides, we get

Here we used ( a+ b)^2 = a^2 + b^2 + 2ab formula.

c - 2 = 5^2 + (√c)^2 + 2(5)√c

c - 2 = 25 + c +10√c

Answer: D) c - 2 = 25 + c + 10√c

Thank you.

4 0
3 years ago
Read 2 more answers
Subtracting 3x^2+4x-5 from 7x^2+x+9
Helga [31]
7x^2+x+9 - (<span>3x^2+4x-5)
= </span>7x^2 + x + 9 - 3x^2 - 4x + 5
= 4x^2 - 3x + 14
8 0
3 years ago
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