What is the ewuation of a line with a slope of 10 that goes theough the point (2,5)

Mathematics

1 answer:

den301095 [7]2 years ago

3 0

Use a graph
Answer: Y=10x-15

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-⅕ (10-5+25x)<br> Please help!

Yanka [14]

Answer:

- $-\frac{1}{5} * (5+25x)\\-\frac{1}{5} *5-\frac{1}{5}(25x)\\-1-\frac{1}{5}(25x)\\-1 -1 (5x)\\01-5x$

Step-by-step explanation:

7 0

3 years ago

Does anyone know how to solve this?

Oksi-84 [34.3K]

Answer: Okay so do 3x7.5 then 3x11.5 then 7.5x11.5 then add it up and you should get 143.25

3 0

1 year ago

Which expression is equivalent to 2(25)

ICE Princess25 [194]

Is this a multiple choice question? If so...what are the options?

6 0

3 years ago

Read 2 more answers

G. Write the equation of the line in slope-intercept form.

Neko [114]

Answer:

y= x-2
y = 4/5 x+39/5

Step-by-step explanation:

$(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{-1} \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2$

$(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\\frac{5y}{5} = \frac{4}{5} x + \frac{5}{5} \\y = \frac{4}{5} x +1\\m = \frac{4}{5} \\\\y -y_1=m(x-x_1)\\y-7=\frac{4}{5} (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = \frac{4}{5} x+\frac{4}{5} +7\\\\y = \frac{4}{5} x +39/5$