Question

A skyscraper is 396 meters tall. At a cenrtain time of day, it casts a showdow that is 322 meters long. At what angle is the sun above the horizon at that time?

Answer 1

Do anybody know the answer to this problem

Answer 2

See image attached. There is a small right triangle formed by the skyscrapper, there is a big right triangle formed by the sun. 
angle $\theta$ on a small and big triangle is the same.

To find the measure of the angle, use trigonometry ratio of tangent
$\text{tan} \theta = \dfrac{\text{opposite}}{\text{adjacent}}$

plug in the numbers
$\text{tan} \theta = \dfrac{396}{322}$
$\theta = \text{tan}^{-1} \left({\dfrac{396}{322} \right)$
$\theta = 50.884^{0}$
or approximately 50°