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Yanka [14]
3 years ago
11

What is the equation of a line perpendicular to the line given by y = (3/7)x+ 9

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

B) y = (-7X/5) + 4

Step-by-step explanation:

Recall two lines are perpendicular if their slopes are negative reciprocals (5/7 goes to -7/5).

Assuming in the form y = mx + b:

Solving for b:

-7/5(-5) + x = 11

(5's & negatives cancel out...)

7 + x = 11

x = 4

y = -7/5x + 4

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Which equation does the model below represent?
qwelly [4]

Answer:

  A. 1.4 / 0.2 = 7

Step-by-step explanation:

Choices A and B are the only true mathematical statements. Of those, choice A seems to best match the model, where each small square represents 0.01 units.

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3 years ago
Myra takes 2hours to plant 50 flower bulbs. Francis takes 3 hours to plant 45 flower bulbs. Working together, how long should it
crimeas [40]

Answer:37 and half hrs


Step-by-step explanation:


This is what I get


Myra: 50/2= 25 bulbs/hr.

Francis: 45/3= 15 bulbs/ hr


25+15= 40/hr. Together per hr

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40/1=150/t

40t=150

T= 150/4

T= 37.5


37hrs and 1/2


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3 years ago
What is the area of a triangle if the top is 3 the left side is 6 and the right side is 6.7
castortr0y [4]

the answer is 120.6 I'm pretty sure

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3 years ago
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Sliva [168]

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yung 70

Step-by-step explanation:

i hope its help

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What is the y- intercept of a line that goes through the points (3,-2)& has a slope of -4?
yulyashka [42]

Answer:

I'm pretty sure that this is correct.

Step-by-step explanation:

this is the equation of a straight line that is generally written

y = m × x + q

m is the slope of the line and is the proportionality coefficient between y and x.

The larger m is, the more the line is hanging

q (-3) is the intercept with the Y axis and is the value you find if you put x=0 (this is the axis y equation)

similarly if you put Y=0 (that is the equation of X axis you find the intercept with X axis that is X= 3/2

graph{2x-3 [-10, 10, -5, 5]}

If I am wrong I am SO SO <em>Sorry.</em> But I hope that I <em><u>Helped!</u></em> :D

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