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Yanka [14]
3 years ago
11

What is the equation of a line perpendicular to the line given by y = (3/7)x+ 9

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

B) y = (-7X/5) + 4

Step-by-step explanation:

Recall two lines are perpendicular if their slopes are negative reciprocals (5/7 goes to -7/5).

Assuming in the form y = mx + b:

Solving for b:

-7/5(-5) + x = 11

(5's & negatives cancel out...)

7 + x = 11

x = 4

y = -7/5x + 4

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I DON'T understand ​
maks197457 [2]

Answer:

f(g(x)) = 72x^2+1

Step-by-step explanation:

f(x) = 2x^2 +1

g(x) = -6x

f°g(x) means f(g(x))

Take g(x) and substitute it in for x in f(x)

f(g(x)) = 2(g(x))^2 +1

           =2(-6x)^2 +1

          =2(36x^2) +1

           =72x^2 +1

8 0
3 years ago
Find the radius of a circle with a circumference of 45(3.14) centimeters
aleksandrvk [35]

C = 2 x pi x r

divide each side by 2 x pie to get r by itself.

45/(2(3.14)) = r

r = 7.17

4 0
3 years ago
Read 2 more answers
Find the slope of the line passing through (-4, 1) and (-1, -2).
Oksana_A [137]

Answer: 1

Step-by-step explanation:

Y2 - Y1 / X2 - X1

-2 - 1 = -3

-1 - -4 = 3

-3/3 = 1

3 0
3 years ago
Read 2 more answers
A hot bowl of soup cools according to Newtons law of cooling. Its temperature (in degrees Fahrenheit) at time t is given by T(t)
nata0808 [166]
212°F
147°F
23.2 min

1) Initial temperature for t=0
T(0)=68+144e^(0)=68+144=212°F
2) After 15 min
T(15)=68+144e^(-0.04*15)=68+144e^(-0.6)=147°F
3) 125°F -> t=?
125=68+144e^(-0.04t)
144e^(-0.04t)=125-68=57
e^(-0.04t)=57/144=0.4 you can apply ln on both sides:
-0.04t=ln(0.4) solving you get t=23.3 min


4 0
3 years ago
Please HELP
eduard

Answer:

Let B = (x, y)

Given A = (8, 9)

distance = \sqrt{(x_1 - x_2)^2 + (y_1-y_2)^2} \\\\10 = \sqrt{(x_1 - 8)^2 + (y_1-9)^2}

option 3

7 0
3 years ago
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