We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students

To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
H(1) = 4
h(1)= 5 x 1 -1
=5-1
=4
hope that helps <3
Estimation:
23 --> rounded to 20
71 --> rounded to 70
70 + 20 = 90. I rounded both numbers down so the exact sum must be only a little greater than my estimate.
For this case defining variables we have:
x: total amount of liters of potting soil.
y: number of liters of potting soil in each pot.
We have then to find the number of pots we use the following expression:
Substituting values we have:
Rewriting we have:
Rounding to the previous whole we have:
Answer:
Yao Xin can fill 18 pots
Answer:
Add 438 + 2 + 60 + 300
440 + 360
Step-by-step explanation:
The last one does not add up to 800
Good luck <3