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Yanka [14]
2 years ago
11

What is the equation of a line perpendicular to the line given by y = (3/7)x+ 9

Mathematics
1 answer:
Nikolay [14]2 years ago
7 0

Answer:

B) y = (-7X/5) + 4

Step-by-step explanation:

Recall two lines are perpendicular if their slopes are negative reciprocals (5/7 goes to -7/5).

Assuming in the form y = mx + b:

Solving for b:

-7/5(-5) + x = 11

(5's & negatives cancel out...)

7 + x = 11

x = 4

y = -7/5x + 4

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A {1,2,3,4}<br> B {2,4,9,16}<br> C {1,2}<br> D {1,2,3,4,9,16}
MaRussiya [10]

Answer:

B

Step-by-step explanation:

The range of the function consists of the set of output values ( on the right).

So its {2 4 9 16}

7 0
3 years ago
Read 2 more answers
How to solve x^2&gt;4x+3
Papessa [141]
Treat this as you would the quadratic equation x^2 - 4x - 3 + 0.   Solve this by completing the square:

x^2 - 4x + 4 - 4 - 7 = 0

(x^2 - 4x + 4) = 11

    (x-2)^2 = 11, and so x-2 = plus or minus sqrt(11).

Graph this, using a dashed curve (not a solid curve).  Then shade the coordinate plane ABOVE the graph.
7 0
2 years ago
How do I solve for h
WITCHER [35]
All the triangles are similar, so the ratio of (long leg)/(short leg) is the same. The long leg of ΔADB is
.. AD = AC -DC = 20 -4
.. AD = 16

Then
.. (long leg)/(short leg) = AD/DB = BD/DC
.. 16/h = h/4
.. h^2 = 64
.. h = 8

Selection D is appropriate.

_____
You may see this again. The altitude (h) from the right angle in a right triangle is the geometric mean of segments AD and DC. That is,
.. h = √((AD)*(DC))
8 0
3 years ago
Find the missing side length
Mashcka [7]
It’s not 3 or 4 so I think 2
7 0
3 years ago
Simplify.
steposvetlana [31]
I hope this helps you



8m+7m+4n-2n


15m+2n
4 0
3 years ago
Read 2 more answers
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