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lbvjy [14]
3 years ago
15

Please help. I really need to pass this.​

Mathematics
2 answers:
Musya8 [376]3 years ago
3 0

Answer:

3.75

Step-by-step explanation:

r²+9²=(6+r) ²

r²+81 = 36+12r + r²

81=36+12r

=> 12r = 45

r = 45/12 = 3.75

vagabundo [1.1K]3 years ago
3 0
3.75 is the correct answer because pemdas
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Read 2 more answers
Solve using the quadratic formula<br> 2x^2+x+67=0
telo118 [61]

Answer:

\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Multiple Roots
  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: \displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

<u>Algebra II</u>

  • Imaginary Root <em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + x + 67 = 0

<em>a</em> = 2

<em>b</em> = 1

<em>c</em> = 67

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [Quadratic Formula]:                                                  \displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}
  2. Multiply:                                                                                                             \displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}
  4. [√Radical] Multiply:                                                                                           \displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}
  5. [√Radical] Subtract:                                                                                          \displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}
  6. [√Radical] Simplify:                                                                                           \displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}
3 0
3 years ago
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