Answer:
.
Step-by-step explanation:
If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is 
.
Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)
Hence, β = - 3 and α + a = 1 and α - a = -3
Now, solving those two equations of α and a we get,
2α = - 2, ⇒ α = -1 and
a = 1 - α = 2.
Now, eccentricity of the hyperbola is given by ![b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20a%5E%7B2%7D%28e%5E%7B2%7D%20%20-%201%29%20%3D%204%5B%28%5Cfrac%7B5%7D%7B2%7D%20%29%5E%7B2%7D%20-1%5D%20%3D%2021)
{Since 
given}
Therefore, the equation of the given hyperbola will be
. (Answer)
Answer:
D, 10.
Step-by-step explanation:
10+8=18 4/3x18=24
Answer:
Step-by-step explanation:
[2,∞)
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
(IN RELATION TO THE PICTURE)
[YES] [YES]
[YES] [NO ]
Step-by-step explanation:
the first number, 2, represents how many wholes are in the group, beings it is separated from the rest of the fraction by a space
the 2/3 is the fraction itself, in this case the last number, 3, is how many pieces the new whole is divided into, wile the first part is how many of those pieces are there
im running on low sleep and ill edit this answer if im wrong, but i hope this helps you with the current problem
