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3 years ago

Olivia makes and sells muffins and scones at

Mathematics

1 answer:

serg [7]3 years ago

8 0

9514 1404 393

Answer:

yes

Step-by-step explanation:

We can substitute the proposed solution values and see if the inequality is true.

0.50x +0.80y ≥ 20

0.50(20) + 0.80(32) ≥ 20

10 + 25.6 ≥ 20

35.6 ≥ 20 . . . . . . true; (20, 32) is a solution

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Roman55 [17]

The fraction in the second parentheses is equal to 3,000. That's also (3 x 10^3). You ought to be able to multiply that by the number in the first parentheses.

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3 years ago

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sveticcg [70]

The surface are of the right cone is 176 sq.units. Option A) is the correct answer.

Step-by-step explanation:

step 1 :

Radius of the cone, r = 4

Height or length of the cone, h = 10

step 2 :

Total surface area of right cone = πrh + πr^2

= (π $\times$ 4 $\times$ 10) + ( π $\times$ 4^2)

= 40π + 16π

= 56 π = 56 $\times$ 3.14

= 176 sq.units

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3 years ago

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Fudgin [204]

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3 years ago

Read 2 more answers

A substance with a half life is decaying exponentially. If there are initially 12 grams of the substance and after 70 minutes th

77julia77 [94]

Answer: 233 min

Step-by-step explanation:

This problem can be solved by the following equation:

$A=A_{o} e^{-kt}$ (1)

Where:

$A=7 g$ is the quantity left after time $t$

$A_{o}=12 g$ is the initial quantity

$t=70 min$ is the time elapsed

$k$ is the constant of decay for the material

So, firstly we need to find the value of $k$ from (1) in order to move to the next part of the problem:

$\frac{A}{A_{o}}=e^{-kt}$ (2)

Applying natural logarithm on both sides of the equation:

$ln(\frac{A}{A_{o}})=ln(e^{-kt})$ (3)

$ln(\frac{A}{A_{o}})=-kt$ (4)

$k=-\frac{ln(\frac{A}{A_{o}})}{t}$ (5)

$k=-\frac{ln(\frac{7 g}{12 g})}{70 min}$ (6)

$k=0.00769995 min^{-1}$ (7) Now that we have the value of $k$ we can solve the other part of this problem: Find the time $t$ for $A=2 g$ .

In this case we need to isolate $t$ from (1):

$t=-\frac{ln(\frac{A}{A_{o}})}{k}$ (8)

$t=-\frac{ln(\frac{2 g}{12 g})}{0.00769995 min^{-1}}$ (9)

Finally:

$t=232.697 min \approx 233 min$

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3 years ago

Please Help!

Nezavi [6.7K]

Let the first number = x

The second number would be 5x

The third number would be 100x

Add:

X + 5x + 100+x = 296

Simplify:

7x + 100 = 296

subtract 100 from both sides:

7x = 196

Divide both sides by 7

X = 196 / 7

X = 28

First number is 28

Second number is 28 x 5 = 140

Third number = 128

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3 years ago