Factor completely 12a^3d^2 – 6ad^3
1 answer:
Answer:
To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5
In the end, the number of times each prime divides the original integer becomes its exponent.
Prime number 2 to the power of 2 equals 4 .
Prime number 3 to the power of 1 equals 3 .
Result:-
<u> OAmalOHopeO</u>
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Answer:
Sam had a finish time with a z-score of -2.93.
Karen had a finish time with a z-score -1.91.
Sam had the more convincing victory.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Sam:
The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.
So
Sam finishing time was 2.93 standard deviations below the mean.
Sam had a finish time with a z-score of -2.93.
Karen:
The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.
So
Karen finishing time was 1.91 standard deviations below the mean.
Karen had a finish time with a z-score -1.91.
Who had the more convincing victory?
Sam finishing time was 2.93 standard deviations below the mean.
Karen finishing time was 1.91 standard deviations below the mean.
Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.
So Sam had the more convincing victory.