Question

Factor completely 12a^3d^2 – 6ad^3

Answer 1

Answer:

$12a^3d^2-6ad^3$

To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5

In the end, the number of times each prime divides the original integer becomes its exponent.

Prime number 2  to the power of 2 equals 4 .

Prime number 3 to the power of 1 equals 3 .

$2^{2} \times 3\times a^{3} \times b^{2} -(2\times3)ad^{3}$

Result:-  $6ad^2\left(2a^2-d\right)$

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