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storchak [24]
3 years ago
5

Help me pleeeassee!!!!

Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

It is the 1st answer.

Step-by-step explanation:

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anita rode her bike for 5.3 kilometers. if she rode her bike 1hour, what would her average speed in kilometers per hour?
pashok25 [27]
How long did she ride it for?

otherwise it would be 5.3 kph
7 0
3 years ago
After deducting 10% provident fund a married person draws Rs 40,500 salary per month and one month's salary as festival bonus, t
olasank [31]

The  annual income tax paid by the person is: $4,500.

<h3>Annual income tax</h3>

Using this formula

Annual income tax=[Salary÷(1-percentage deduction)]- Salary

Let plug in the formula

Annual income tax=[40,500÷(1-10%)]-40,500

Annual income tax=45,000-40,500

Annual income tax=4500

Therefore the  annual income tax paid by the person is: $4,500.

Learn more about annual income tax here:brainly.com/question/26316390

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6 0
2 years ago
The midpoint of AB is M(2, -1). If the coordinates of A are (1,6), what are the
VashaNatasha [74]

Answer:

work is attached and shown

5 0
3 years ago
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
Sam is walking across a bridge and accidentally drops an orange into the river basin below
irina1246 [14]

Answer:

We assume that the orange is dropped at t = 0s.

Once the orange is on the air, the only force acting on it is the gravitational force, then the acceleration of the orange is the gravitational acceleration.

A(t) = -32.17 ft/s^2

Where the negative sign is because this acceleration points downwards.

For the velocity equation, we need to integrate over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial vertical velocity of the orange, because the orange is accidentally dropped, this initial velocity is equal to zero.

V(t) =   (-32.17 ft/s^2)*t

For the position equation we need to integrate again, this time we get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the orange, we know that it is 40ft, then the position equation is:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft

Now that we know the equation, we can graph it. (you can see the graph below)

Now we also want to find at what time does the orange hit the water.

This happens when:

P(t) = 0 ft =   (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft

We just need to solve that equation for t.

0 ft =   (1/2)*(-32.17 ft/s^2)*t^2 + 40 ft

(1/2)*(32.17 ft/s^2)*t^2 =  40 ft

t^2 = (40ft)/( (1/2)*(32.17 ft/s^2))

t = √(  (40ft)/( (1/2)*(32.17 ft/s^2)) ) = 1.58 s

The orange hits the water 1.58 seconds after it is dropped.

3 0
2 years ago
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