<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
As the question states,
John's brother has Galactosemia which states that his parents were both the carriers.
Therefore, the chances for the John to have the disease is = 2/3
Now,
Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.
Now, one of those children married with a person.
So,
Probability for the child to have disease will be = 1/2
Now, again the child's child (Martha) probability for having the disease is = 1/2.
Therefore,
<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)
<em><u>Hence, the probability for the first child to have Galactosemia is
</u></em>
-7/9 is repeating
42/50 is terminating
-1/125 is terminating
-77/600 is repeating
179/200 is terminating
5/11 is terminating
The way to figure this out is just by dividing the Numerator (top number) by the denomiter (bottom number)
Example 5÷11=.45454545 repeating
There is a 2 of 6 percent chance that one them might land on three if you add one extra dice it would be 3 of 6 percent chance and so on.
Hope this Helped!
;D
Brainliest??