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3 years ago

30 pts AWNSER ASAP In 2 hours, Nolan can bake 5 1/2 dozen cookies. What is his unit rate in dozen cookies per hour?

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

2 3/4 dozen cookies per hour

Step-by-step explanation:

To find his unit rate per hour, divide 5 1/2 by 2:

5.5/2

= 2.75 or 2 3/4 dozen cookies

So, his unit rate in dozen cookies per hour is 2 3/4

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I don’t know how to do this I am very bad at math

maw [93]

Answer:

Surface area= 7.5

Step-by-step explanation:

The area of a triangle is b*h/2. so if you fill in the numbers your equation would be 5*3/2. 5*3=15 and 15/2=7.5

hope this helps!!

5 0

3 years ago

HELPPP!!!

xxMikexx [17]

The angles ∠CFE and ∠AFB are vertically opposite angles. Then the value of x will be 6.

<h3>What is an angle?</h3>

Angle is the space between the line or the surface that meets. And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.

Vertically opposite angle - When two lines intersect, then their opposite angles are equal.

We know that the angle ∠DFE is 90°.

Then the sum of the angle ∠CFD and ∠DFE will be

∠CFD + ∠DFE = 27° + 90°

∠CFD + ∠DFE = 117°

Then the angles ∠CFE and ∠AFB are vertically opposite angles. Then we have

∠CFD = ∠DFE

Put the values

21x - 9 = 117

21x = 126

x = 6

More about the angled link is given below.

brainly.com/question/15767203

#SPJ1

8 0

2 years ago

What is 1/2k-3=2-3/4K

laiz [17]

Answer:

1/2k-3=2-3/4k

1/2k+3/4k=2+3

1.25k=5

1.25k/1.25=5/1.25

k=4

4 0

3 years ago

Find the gradient of the line Joining the points p(-2,6) and Q(3,-2)

Rudiy27

Answer:

$- \frac{8}{5}$

Step-by-step explanation:

$\boxed{gradient = \frac{y1 - y2}{x1 - x2} }$

(x₁, y₁) is the 1st coordinate while (x₂, y₂) is the 2nd coordinate.

Gradient of the line

$= \frac{6 - ( - 2)}{ - 2 - 3}$

$= \frac{6 + 2}{ - 5}$

$= - \frac{8}{5}$

7 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

3 years ago