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photoshop1234 [79]
3 years ago
14

What are the solutions of 6x2 − 216 = 0?

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0
The solutions are -6 and 6

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19x+46=<br> help meeeeeeeeeeee
strojnjashka [21]

Answer:

u just add it

Step-by-step explanation:

3 0
3 years ago
Solve. (x + 3)^1/2– 1 = x
Natali [406]

Answer:

x=1

Step-by-step explanation:

(x + 3) ^{ \frac{1}{2} }  - 1 = x  \\  \sqrt{x  + 3}   - 1 = x \\  \sqrt{x + 3}  = x + 1 \\ square \: both \: sides \\ x + 3 =  {x}^{2}  + 2x + 1 \\  {x}^{2}  + 2x - x + 1 - 3 = 0  \\  {x}^{2}  + x - 2 = 0  \\ x ^{2}  + 2x - x - 2 = 0  \\ (x^{2}  + 2x) - (x  + 2) = 0 \\ x(x + 2) - 1( x + 2) = 0 \\ (x - 1)(x + 2) = 0 \\ x - 1 = 0 \\ x = 1 \\  \\  \\ x  +  2 = 0 \\ x =  - 2

8 0
3 years ago
Find the volume of the solid below.
Semenov [28]

Answer:

Volume = V=  346.43 cm ^3

Step-by-step explanation:

15.32 x 10 = 153.2cm Area of side

We find the height of the cylinder, to enable the radius/2 for the circle side x 2

it would be the same as triangle side 6 but the exact circumference is worked out at 6.37

We start by finding the side

As a = half circumference = 20 x sin (30) =10 we x2 for full circumference, then divide by pi

10 +10 =20cm  circumference.

20/6.28 =3.1847133758 = radius

we x 2 and find the height

3.1847133758 x 2  = 6.3694267516

rounded to nearest 10th = 6.4 units exact 6.37

We find other measurements before calculating volume.

and b =  √400-√100 = √300

b= 17.32 (height for volume use) or length of right side cylinder

c= 20 hypotenuse.

Volume = πr2h

V= 3.14 * 6.37 * 17.32 =346.43

V=  346.43 cm ^3

V= 346 cm ^3 to nearest 10th

V= 346.43 cm^3

5 0
3 years ago
Select the correct answer.
Digiron [165]
C because if you plug one into the other the answer comes out as x and that is how you know it is an inverse
7 0
2 years ago
A student of the author earned grades of 92, 83, 77, 84, and 82 on herfive regular tests. She earned grades of 88 on the final e
goblinko [34]

The class is weighted as follows:

60% Regular Tests

10% Final Exam

15% Project

15% Homework

The total weighted points possible for the class are as follows:

(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340

To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:

(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4

So her weighted grade percent would be 285.4/340 = 83.9% which is a B.

8 0
3 years ago
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