Answer:

Step-by-step explanation:
Half the length of the palindrome can be any possible sequence of the 26 available letters. The other half is constrained to be the reverse of the same sequence. For odd length sequences, the middle letter can be any of the 26.
So, for k even, the number of palindromes is 26^(k/2). For k odd, the number is 26·26^((k-1)/2) = 26^)((k+1)/2).
8 were defective.
Defective percent = 8/84 x 100 = 9.5238% were defective.
Percent not defective = 100% - 9.5238% = 90.4761%
Rounding to the nearest tenth 90.5% were not defective.
The question doesn’t say how to round the answer so you may need to round differently than I did.
Sajia can sell 21 books she can sell if she comes back on sunday and the required inequality is 
<em><u>Solution:</u></em>
Given that Sajia has 30 Books in her library
She sold 9 books at the thrift store on Saturday
To find: We have to write and solve an inequality to determine number of more books she can sell if she comes back on sunday
Let "x" be the number of more books she can sell if she comes back on sunday
<em><u>We can write a inequality as:</u></em>


Now moving 9 from L.H.S to R.H.S we get,

On solving 30 - 9 = 21,

So Sajia can sell 21 books she can sell if she comes back on sunday
The answer is nine. You can write 27 as 27/1. From there, just multiply the fractions.
27/1 x 1/3 = 9
Use the formula a = a+b/2h