Find the sum and express it in the simplest form. (2x^2+3x-4)+(x^2-x-2)

Mathematics

1 answer:

Katen [24]3 years ago

8 0

18 hope it helped!!

:) be my pleasure!

tysm

You might be interested in

PLEASE PLEASE PLEASE PLEASE (5'1, 5'2, 5'3, 5'4, 5'5, 5'6, 5'7, 5'8, 5'9, 5'9, 5'10, 5'11, 5'12)

Yakvenalex [24]

Answer:5

5 feet 7 inches

Step-by-step explanation:

first add all of the given together and then divide what you get by the number of terms given

(5'2+5'3+5'4+ 5'5+5'6+ 5'7+ 5'8+5'9+5'9,+5'10+5'11+5'12)/12 = 5'7 11/64 inches

then divide 11 by 64 on a calculator and then round the decimal you get to the nearest tenth which gives you the answer 5 feet 7 inches.

4 0

2 years ago

How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

8 0

3 years ago

What is the value of x?<br> *36<br> *72<br> *108<br> *144

Anit [1.1K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Input divided by two plus one is the output

Naily [24]

The equation to this problem would be y = x/2 + 1

3 0

3 years ago

Please help me out ?

vova2212 [387]

An obtuse triangle is formed if there is an angle that has a measure of more than 90 degrees. You can determine if an obtuse angle is formed by two sides of a triangle if it meet this condition:

Let a and b be two sides of a triangle and c is the longest side:
$a^{2} + b^{2} \ \textless \ c^{2}$

So taking your given:

$10^{2} + 15 ^{2}$ < $c^{2}$
100 + 225 < $c^{2}$
325 < $c^{2}$

To get the smallest possible number, just get the square root of both sides:

$\sqrt{325}$ < $\sqrt{c^{2} }$
18.03 < c

So your smallest possible whole number is 19

5 0

4 years ago