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makvit [3.9K]
3 years ago
10

Find the sum and express it in the simplest form. (2x^2+3x-4)+(x^2-x-2)

Mathematics
1 answer:
Katen [24]3 years ago
8 0
18 hope it helped!!



:) be my pleasure! 


tysm
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Help me anyone that great in math
pochemuha

Answer:

B) 24/35

Step-by-step explanation:

Cos(X)= Adjacent/Hypotenuse

Cos(X) = 24/25

Therefore, option B is your answer.

Hope this answers your question!!

6 0
2 years ago
The logo for Chris's Calculator Company is 3 semicircles. The logo will be placed on the company building and will be 4 feet tal
kotegsom [21]

18.84 ft 2

37.68 ft 2

50.24 ft 2

75.36 ft 2

8 0
3 years ago
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Jim earned $140 during the summer doing chores. He bought 2 sets of pens worth $25 each using his chore money. How much money wa
Degger [83]
Jim has $90 from is chore money left.

6 0
3 years ago
Read 2 more answers
Helppppp
sasho [114]

Answer:

186.5 + 2x

Step-by-step explanation:

First, radify 25. Luckily it's a perfect square so it will be 5.

Second, divide within the parentheses. You're expression should look like this.

(93-5+x+42/8)2

Divide 42/8. The decimal form would be 5.25, while the fraction should be 5 1/4.

Third, solve within the parentheses from left to right. Right now you're expression should look like this:

(93-5+x+5.25)2

Add all like terms

93-5+5.25=93.25

Fourth, multiply. Right now the expression should look like this:

(93.25 + x) 2

186.5 + 2x

8 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
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