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777dan777 [17]
3 years ago
5

When we compare two fractions with the same numerator, which

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

The fraction with the smaller denominator is the larger fraction.

Step-by-step explanation:

Let's take \frac{5}{6} and \frac{5}{10}. The larger the denominator, the more the number of pieces. So if you have a  pizza box divided into 6 slices, and they are all the same size, compared to that same box of pizza divided into 10 slices. Each of those 10 slices will be smaller than the 6 slices. Now if you eat 5 of the 6 slices, compared to if you eat 5 of the 10 slices, which one will make you more full and you know that you have eaten a lot? Of course, it is the 5 out of 6 slices because each of those slices is bigger. So the smaller the denominator of the fraction, the larger it is (if the numerator stays the same).

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the answer is DBC=90°

because the midpoint of the perimeter of quadrilateral is B

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The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d
aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

<h3 /><h3>Step 1</h3>

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

f(t)=\left \{ {{0 ,\-t

Consider the second function:

f(t)=\frac{e^{-t/\mu}}{\mu}\\

Where Average waiting time = μ = 2.5

The function f(t) becomes

f(t)=0.4e^{-0.4t}

<h3>Step 2</h3>

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt

which is equal to 0.01

<h3>Step 3</h3>

Solve the equation for x

\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01

Take natural log on both sides

ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

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3 years ago
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Answer:

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Step-by-step explanation:

we know that

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y-y1=m(x-x1)

in this problem we have

m=\frac{1}{3}

(x1,y1)=(3,2)

substitute the values in the formula

y-2=\frac{1}{3}(x-3)

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1/600, 6/100, 1/1400

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