Answer:
(a) 5
(b) 3rd quartile
(c) 2nd quartile
Step-by-step explanation:
There are four quartiles in a box plot <em>(or box and whisker plot).</em>
The 1st is from 5 to 13
The 2nd is from 13 to 35
The 3rd is from 35 to 40
The 4th is from 40 to 48
<em />
(a) The lowest that this box plot goes is 5 <em>(between the 4 and 6)</em>
(b) 3rd quartile — we can see that the left and right borders are close together, meaning that the data values for this quartile are close together, and therefore concentrated
(c) 2nd quartile — we can see that this quartile is the widest, and therefore the data values are spread out
<h3>s³=l,b,h</h3><h3>so,</h3><h3>s³=125</h3>
![s = \sqrt[3]{125}](https://tex.z-dn.net/?f=s%20%3D%20%20%5Csqrt%5B3%5D%7B125%7D%20)
<h3>s=5 and height =5 cubes</h3><h3>hope it helps :-)</h3>
Answer:
look at the picture i have sent
56 and five gf sbhdjd f fbdbfbfbd dc
Let, length and breadth of rectangle is L and B respectively.
It is given that :
The length rectangle is 4 cm more than 3 times the width of the rectangle.
L = 3B + 4 ......1 )
Also, area of square = area of the rectangle + 66
L² = LB + 66
Putting value of L from
L² = ( 3B + 4 )( B ) + 66
L² = 3B² + 4B + 66
( 3B + 4 )² = 3B² + 4B + 66
9B² + 16 + 24B = 3B² + 4B + 66
6B² + 20B - 50 = 0
3B² + 10B - 25 = 0
3B² + 15B - 5B -25 = 0
3B( B + 5 ) -5( B + 5 ) = 0
B = 5/3 units
L = 3( 5/3 ) + 4
L = 5 + 4 = 9 units
Hence, this is the required solution.
