You are adding s^2 to your 128 ft^2. s^2 is a common representation of a square. So you could think of it as adding an area of a square of side "s" to your deck.
So one way of drawing it is to draw a rectangle with area 128 ft^2 and attaching a square to one of its side. The square that is attached has a side lenght of "s."
<h3>Answer: C) none of the equations are identities</h3>
If you plugged theta = 0 into the first equation, then you would have
sin(45) + cos(45) = sin(0) + cos(0)
sqrt(2) = 1
which is a false equation. We don't have an identity here.
The same story happens with the second equation. Plug in theta = 0 and it becomes
cos(60) - sin(60) = cos^2(0) + tan(0)
1/2 - sqrt(3)/2 = 1 + 0
-0.37 = 1
which is false.
Answer:
$1,109.80
Step-by-step explanation:
$3580 times 31% = 1,109.80+ 3580 = $4,689.80
Answer:
Options B and D.
Step-by-step explanation:
The general form of sine function

where, |A| is amplitude,
is period,
is phase shift and D is y-intercept.
The general form of cosine function

where, |A| is amplitude,
is period,
is phase shift and D is y-intercept.
In function, 
Amplitude : 
y-intercept : -1
In function, 
Amplitude : 
y-intercept : -1
In function, 
Amplitude : 
y-intercept : 0
In function, 
Amplitude : 
y-intercept : -1
Therefore, the correct options are B and D.
Answer:
A. a rectangle and a triangle