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Ymorist [56]
3 years ago
14

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi

ch table of values matches the equation and includes only viable solutions?.
Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable. The values given in the table 3 matches the equation and includes the viable solutions.

<h3>Given information-</h3>

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation,

c=3.5b

The quantity of the bread depends on the quantity of the loaves.

<h3>Dependent variable</h3>

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable.

Lets check which table satisfy the above equation.

Table 1-

In the table the first values of the bread and the loves is -2 and -7. The quantity of a bread and loves can not be negative. Thus the table 1 does not provides the viable solution.

Table 2-

In the table 2 the value of the third row is 1.5 loaves and 5.25 breads. Check this by the given equation. When the value of loaves is 1.5 then the value of the bread is,

c=3.5\times1.5

c=4.5

The value of bread must be 4.5. Thus the table 2 does not provides the viable solutions.

Table 3-

Put the values of the loaves in the given equation one by one,

When the value of loaves is 0 then the value of the bread is,

c=3.5\times0=0

When the value of loaves is 3 then the value of the bread is,

c=3.5\times3=10.5

When the value of loaves is 6 then the value of the bread is,

c=3.5\times=21

When the value of loaves is 9 then the value of the bread is,

c=3.5\times9=31.5

All the values of the table 3 satisfies the given equation.

Hence, the values given in the table 3 matches the equation and includes the viable solutions.

Learn more about the dependent variables here;

brainly.com/question/967776

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Math question need help with substation please?
Juliette [100K]

<em>2 solutions</em>

<em>X= 16</em>

<em>X=49</em>

Step-by-step explanation:

<em>original equation</em>

<em>x-11√x+28 = 0</em>

<em>   Isolate</em>

<em>     -11√x = -x-28+0</em>

<em>  Tidy up</em>

<em>     11√x = x+28</em>

<em>  Raise both sides to the second power</em>

<em>     (11√x)2 = (x+28)2</em>

<em>After squaring</em>

<em>     121x = x2+56x+784</em>

<em> Plug in 49 for  x </em>

<em>      11√(49) = (49)+28</em>

<em>Simplify</em>

<em>      11√49 = 77</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 49

<em>Plug in 16 for  x </em>

<em>      11√(16) = (16)+28</em>

<em>Simplify</em>

<em>      11√16 = 44</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 16

3 0
3 years ago
ON A RECENT MATH TEST MARY SCORED 14 OF 16 CORRECT. JOHN SCORED 23 OF 26AND JOE SCORED 9 OF 11 CORRECT. WHO ACHIEVED THE HIGHER
Andrej [43]

Answer:

I think the answer is mary

7 0
3 years ago
Read 2 more answers
Please help
vagabundo [1.1K]
I would say no to that.
4 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
Tiana is on a 25-foot ladder that is leaning against her house. Its base is 7 feet from the base of the house. The ladder slips
Lostsunrise [7]

Answer:

4 ft downwards

Step-by-step explanation:

old height off the ground :

7^2+b^2=25^2

49+b^2=625

b^2=576

b=24

new height off the ground :

7+8=15

15^2+ b^2 =25^2

225+b^2 = 625

b^2 = 400

b=20

difference between heights :

24 - 20 =  4

4 0
4 years ago
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