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3 years ago

5. Find the value of x. 30° (3x - 10)

Mathematics

2 answers:

djyliett [7]3 years ago

8 0

See attachment for math work and answer.

Vaselesa [24]3 years ago

5 0

This is the answer I think not sure but hoped it helped

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A diagonal of a cube measures 15cm and the length of the edge of the cube is 75cm. What is the length of a face of the cube? Rou

zmey [24]

The answer is 69

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3 years ago

I need help with this page

Alika [10]

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2 years ago

Which methods correctly solve for the variable n in the equation 11−n=−20? Select all that apply. First, add n to both sides. Th

Zina [86]

Answer:

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, add 20 to both sides.

Step-by-step explanation:

Given equation:

11 - n = -20

Solve for variable n

11 - n = -20

Subtract 11 from both sides

11 - n - 11 = -20 - 11

- n = - 31

Multiply both sides by -1

- n(-1) = - 31(-1)

n = 31

First, subtract 11 from both sides. Then, multiply both sides by −1.

11 - n = -20

11 -n +n = -20 + n

11 = -20 + n

11 + 20 = -20 + n +20

31 = n

First, add n to both sides. Then, add 20 to both sides.

First, subtract n from both sides. Then, multiply both sides by −20.

First, add n to both sides. Then, subtract 11 from both sides.

11 - n = -20

11 - n +n = -20 + n

11 = -20 + n

11 - 11 = -20 + n -11

Not possible

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, subtract 20 from both sides.

11 - n = -20

11 - n + n = -20 + n

11 = -20 + n

11 - 20 = -20 + n - 20

9 = n - 40

Not possible

5 0

3 years ago

!!! 25 POINTS HELP PLS

weqwewe [10]

Answer:

Option (3)

Step-by-step explanation:

Given functions are,

f(x) = $\frac{1}{4^x}$

g(x) = log(2x)

By using a graphing utility we can draw the graphs of the given system of equations.

Common points of the graph will be the solutions of the equations,

From the graph attached,

Solution of the functions is → (0.937, 0.273)

→ (0.9, 0.3)

Option (3) will be the answer.

3 0

3 years ago

A recent survey found that 65% of high school students were currently enrolled in a math class, 43% were currently enrolled in a

Bas_tet [7]

<h3>Answer: Choice A) 0.20</h3>

===================================================

Explanation:

Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.

65% of them are in math. So there are 0.65*1000 = 650 math students.
43% are in science, leading to 0.43*1000 = 430 science students.
13% are in both so we have 0.13*1000 = 130 students who are in both.

Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"

This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.

Of those 650 math students, 130 are also in science (since 130 are in both classes).

The probability we're after is therefore 130/650 = 0.20

4 0

3 years ago

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