See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
A part of a line that connects two endpoints I believe
Answer:
x=44, They are adjacent
Step-by-step explanation:
since this is right angle it is 90 degrees. You set the whole thing equal to 90, so 43+x+3=90, add 43 and 3=46. Then you subtract 90-46, you get x=44.
Answer:
11.9 miles
Step-by-step explanation:
The length of the track is ...
C = 2πr = 2π(200 ft) = 400π ft
Then the length of 50 laps will be ...
50C = 50·(400π ft) = 20,000π ft ≈ 62,831.9 ft
The number of miles (m) this is can be found from ...
m(5280 ft) = 62,831.9 ft
m = 62,831.9/5280 ≈ 11.90 . . . . miles
50 laps is about 11.9 miles.
The answer is the last option because the graph goes no greater than 75 and it also goes no greater than zero but it does hit zero and 75