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2 years ago

Order each set of fractions as indicated: 1/9, 1/20, 1/25, 1/2, 1/50

1 answer:

3 0

Use the least common denominator (LCD) to write these fractions as equivalent fractions with like denominators, and then compare them two at a time

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How many lines of symmetry does a kite have? 4 3 1 2

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A typical quadrilateral kite (kinda looks like a diamond) only has 1 line of symmetry

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2 years ago

Someone help with this please

r-ruslan [8.4K]

The Answer is B. I hope this helped.

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2 years ago

Suppose that a 2 by 10 rectangular grid of seats is filled with people. On the

IrinaVladis [17]

There are 20! number of ways for everyone to do this so that at the end of the move, each seat is taken by exactly one person.

People are seated in a 2 by 10 rectangle grid. All 20 persons stand up from their seats and relocate to an orthogonally neighboring one upon the blowing of a whistle.

Now, we have to find the number of possible ways in which each seat is taken up by exactly one person after the move.

As the number of people is 20 and 20 seats are to filled exactly once.

So, the number of ways = 20!

Learn more about number here:

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1 year ago

PLease help ill give brainliest

stepan [7]

A bar graph is when you want to compare the data in the data set (which this data set does)

A line graph is used when the data set creates a straight line (which this data set does not)

A circle graph (also known as a pie chart) is used when the data set measures percentages that will total 100% (which this data set does not)

A stem plot is used when you want to show the frequency of the beginning digit <em>or digits</em> (which this data set does not)

Answer: A

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2 years ago

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

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2 years ago