Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
10² - 2 (8) + 11 . Use PEMDAS, which is the order of operation to follow:
P = parenthesis → 10² - 2x8 +11
E = exponent → 100 - 2x8 +11
M = Multiplication → 100 -16 +11
D = Division → NO DIVISION
A = Addition → 111 -16
S = Subtraction → 95 (answer 3)
Apply the same logic for the 2nd exercice and you will find 26 (I don't see the 26 in your answer but I am sure it's 26)
Answer:
y = (-3/4)x - 4
Step-by-step explanation:
The slopes of perpendicular lines are opposite reciprocals of each other. In other words, if the slope of one line is a/b, then the slope of the line perpendicular to it would be -b/a.
Here, the given slope is 4/3, so the slope of the perpendicular line is -3/4.
We are given a point (-4, -1) and we know the slope, so we can find the point-slope form of the line. Point-slope form is written as y - y1 = m(x - x1), where (x1,y1) is the point and m is the slope. Here, x1 = -4 and y1 = -1 and m = -3/4. So:
y - y1 = m(x - x1)
y - (-1) = (-3/4) * (x - (-4)) = (-3/4) * (x + 4)
y + 1 = (-3/4)x + (-3/4) * 4 = (-3/4)x - 3
y = (-3/4)x - 3 - 1
y = (-3/4)x - 4
