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Nikitich [7]
3 years ago
7

Candy has to paint a fence if she can paint 2/3 of each section in 1/2 and hour and there are 9 sections how long will it take h

er to paint the entire fence
Mathematics
1 answer:
aev [14]3 years ago
5 0
Do you mean half an hour because if she can paint 2/3 of each section in half an hour, it would take her 3 hours to paint all 9 sections. I hope this is correct.
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A bouncy ball is dropped such that the height of its first bounce is 3.25 feet and each successive bounce is 71% of the previous
grigory [225]

Answer:

i do not know bro for real this aint no game at all

8 0
2 years ago
Number 6 part a &amp; b<br> Number 7<br> Please &amp; thank you
miv72 [106K]

Answer:

6- Part A: 750a+1200r=1000000

    Part B: 1065a+876r=1000000

Solution of the system: a\approx521.739\;\;\;\;b\approx507.246

Step-by-step explanation:

<u>Part A:</u>

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

750a+1200r=1000000

<u>Part B:</u>

In words:

Arabica's worth + Robusta's worth  = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000

3 0
3 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
What is the smallest number with the factors 1,2,3,4, and 5? What is the special name for it?
klasskru [66]
To find LCM
factor and eliminate ones already represented
1=1
2=2
3=3
4=2*2
5=5

1*2*2*3*5=60
7 0
3 years ago
5,7,11,17,25__ find the missing number
Anton [14]
The answer is 35 please rate me the brainlest answer

5 0
3 years ago
Read 2 more answers
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