Answer:

Step-by-step explanation:
Given
Points: (1, 9) and (9, 3)
Ratio = 2/3
Required
Determine the coordinate of the center
Represent the ratio as ratio

The new coordinate can be calculated using

Where



Substitute these values in the equation above



Hence;
<em>The coordinates of the new center is </em>
<em></em>
Answer:
B (2, 2)
Step-by-step explanation:
Given the graphs of a system of equations then the solution is at the point of intersection of the 2 lines.
That is (2,2) ← is the solution → B
Answer:
3
Step-by-step explanation:
1/4 = 2/8
With 7/8 pounds of meat, you can make 3 patties (6/8) and have 1/8 pound leftover
We are given equation :




Therefore, final factored form it

We can't factor it more.
Therefore,
x+1=0.
x=-1.
Therefore, the real solution of the equation would be -1.