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alexandr1967 [171]
3 years ago
11

for a class gardening project 1/3 of mrs gordon's students planted marigolds and 1/2 planted tulips what fraction of the class p

lanted either marigolds or tulips
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
Get them to have a common denominator so you can add them
(1/3)×2= 2/6 and (1/2)×3= 3/6
Add them together
(2/6)+ (3/6)= 5/6
So 5/6 of the class planted either marigolds or tulips and 1/6 of the class planted neither
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The equation for the circle below is x^2+y^2=64 what is the length of the circle’s radius
FromTheMoon [43]

Answer:

<h2>r = 8</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

x^2+y^2=64\\\\(x-0)^2+(y-0)^2=8^2

Therefore the center is (0, 0) and the radius r = 8

3 0
3 years ago
Consider the line y= -5/2x +6 what is the slope of the parallel line
zepelin [54]

Answer:

The equation is not linear so the slope does not exist. And neither does a slope for the parallel line.

Step-by-step explanation:

Good luck xx

4 0
3 years ago
3/7 of the people living in the apartment building are men. 5/8 of the remaining are women. The rest are children. A total of 27
Vladimir [108]
People in building ---- x (men, women and children)
children --- y
men + women + children = x
(3/7)x + (5/8)(4/7)x + y = x
3x/7 + 5x/14 + y = x
times 14
6x + 5x + 14y = 14x
14y = 3x

y + 220 =x
sub into the other one
14y = 3(y+220)
11y = 660
y = 60
then 14(60) = 3x ---> x = 280

So we have 280 people in the building.

check: 3/7 of 280 are men = 120
leaving 160 women and children
5/8 of these ot 100 are women

so we have 120 men, 100 women and 60 children!

hope this is right! have a great. day
7 0
3 years ago
Fill in the blank. The centroid is (blank) of the distance from each vertex to the midpoint of the opposite side.
Andre45 [30]

Step-by-step explanation:

.

The centroid is 2/3 of the opposite side. of the distance from each vertex to the midpoint. 8. To inscribe a circle about a triangle, you use the.

5 pages·2 MB

7 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
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