if the sides of a triangle QRS are QR=10X-6, RS=6X-15,QS=X+24, find a range of possible values for X?
1 answer:
You might be interested in
9514 1404 393
Answer:
√3/11, π/24, 3/25, 9/100
Step-by-step explanation:
The 2-decimal value of each of the numbers is ...
9/100 = 0.09
π/24 = 0.13
3/25 = 0.12
√3/11 = 0.16
Then the order from greatest to least is 0.16, 0.13, 0.12, 0.09. In the original form, that is ...
√3/11, π/24, 3/25, 9/100 . . . . . matches choice B
