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galina1969 [7]
3 years ago
14

In an injection-molding operation, the length and width, denoted as X and Y, respectively, of each molded part are evaluated. Le

t A denote the event of 48 < X < 52 centimeters B denote the event of 9 < Y < 11 centimeters. Construct a Venn diagram that includes these events. Shade the areas that represent the following:
a. A
b. A ∩ B
c. A' ∪ B
d. A ∩ B
e. If these events were mutually exclusive, how successful would this production operation be? Would the process produce parts with X = 50 centimeters and Y = 10 centimeters?
Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

attached below

Step-by-step explanation:

Attached below are the Venn diagrams

A :  48 < X < 52   cm

B : 9 < Y <  11 cm

a) A

b) A ∩ B

c) A' ∪ B

d) A ∪ B

e)  for events to be mutually exclusive it means that both events can not occur simultaneously i.e. A ∩ B = 0

the process would not be successful hence the process would not produce parts with X = 50 cm and Y = 10 cm

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The area of the trapezoid is 57.5 square inches

Step-by-step explanation:

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see the attached figure to better understand the problem

step 1

The area of rectangle is given by the formula

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1) El largo de un rectángulo mide el triple que su ancho. Si el ancho mide 12 cm, el perímetro del rectángulo es: Selecciona la
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Answer:

1) c) 96 cm

2) c) 17,15 m

3) c) 294 m

4) d) 332 metros

Step-by-step explanation:

1)

La fórmula para el perímetro de un rectángulo = 2L + 2W

= 2 (largo + ancho)

L = longitud

W = ancho

Se nos dice en la pregunta que:

La longitud de un rectángulo es tres veces su ancho. Si el ancho es de 12 cm

Por lo tanto,

L = 3 W

L = 3 × 12

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= 2 (36 + 12) cm

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2)

La fórmula para el perímetro de un heptágono regular = 7a

Donde a = longitud de un lado

De la pregunta,

a = 2,45 m laterales

Por lo tanto, el perímetro de un Heptágono regular = 7 (2,45 m)

= 17,15 m

3)

La fórmula para el perímetro de un rectángulo = 2L + 2W

= 2 (largo + ancho)

L = longitud

W = ancho

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Si un campo de fútbol tiene 98 m de largo y su ancho es igual a la mitad de esta medida,

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El parque es de forma rectangular.

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1 milímetro = 0,001 metro

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= 2 (45 + 38)

= 2 (83)

= 166 m

Distancia alrededor del parque una vez = 166 m

Pero nos dijeron que dio la vuelta al parque 2 veces, por lo tanto, la distancia que recorrió = 166 m × 2

= 332m

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