21.00 you would take and fine the how much 40 percent of 35 is then subtract it so 35*40/100=14 35-14=21
Answer:
I think what you meant to say is "If a triangle has 2 sides that are 4 cm and 20 cm, what are the possible lengths of the third side?"
Basically, when given 2 sides of a triangle, the third side must be GREATER than the DIFFERENCE of the other 2 sides and LESS than the SUM of the other 2 sides.
difference = 16 cm
sum = 24 cm
So, the third side must be greater than 16 cm and less than 24 cm
Step-by-step explanation:
Answer:
Class width = 9
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
Step-by-step explanation:
We are given;
Highest value = 82
Lowest value = 20
Frequency = 7
Formula for class width is;
Class width = (Highest Value - Lowest Value)/number of classes
Class width = (82 - 20)/7
Class width = 8.8 ≈ 9
Now,since class width is 9, limits between 20 and 82 would be done at intervals of 9.
Thus;
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
8+7=15
300/15=20
8 x 20 =160 Boys
7 x 20 = 140 girls
140 + 160 = 300
Hope this helps!
