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Stels [109]
3 years ago
14

ABC is dilated by a factor of 1/2 to produce A'B'C'

Mathematics
2 answers:
Anton [14]3 years ago
5 0

Answer:

B

Step-by-step explanation:

34 x 1/2 = 17 (Line A'B')

28 x 1/2 = 14 (Angle A')

allochka39001 [22]3 years ago
5 0

Answer:

b

Step-by-step explanation:

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Mary mixes white paint in the ration 2:3
topjm [15]
11 more liters because then the ratio would be 2:14 which is equal to 1:7
8 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
Need help asap !
frutty [35]
The triangle to solve for has a leg or 12 feet, hypotenuse of 20 feet, so solve for Pythagoras a^{2}  +  b^{2}  =  c^{2}  for a

a =  \sqrt{c^{2} -b^{2}}

a = 16 feet
5 0
3 years ago
Find the 97th term of the arithmetic sequence
kozerog [31]
<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1  = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, a_{n}  = a_{1} + (n - 1) d

Substituting the values in the above equation, we get

a_{97}  = 25 + (97 - 1) 4

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

3 0
2 years ago
Help (pic attached!!)
mash [69]
( \sqrt[5]{ 3^{2} } )^{ \frac{1}{3} } =  (3^{ \frac{2}{5} } ) ^{ \frac{1}{3} } = 3^{ \frac{2}{15} }

Answer: C.
7 0
3 years ago
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