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2 years ago

PLEASE HELP ME!!!!!! Write the information in the table as ordered pairs. Graph the relationship from the table.

Mathematics

1 answer:

Sliva [168]2 years ago

4 0

Answer:

(3, 60) (5, 100) (8, 160) (9, 180) (12, 240)

Step-by-step explanation:

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14)

poizon [28]

Answer:

f(x) = 2x+5

Step-by-step explanation:

Given the arithmetic sequence shown

7,9, 11, 13, 15, 17,

THe nth term of the sequence is expressed as;

Tn = a + (n-1)d

a is the first term = 7

d is the common difference = 9-7 = 11-9 = 2

Substitute

Tn = 7 + (n -1)*2

Tn = 7 + 2n - 2

Tn = 2n + 5

Hence the required function is f(x) = 2x+5

4 0

2 years ago

1. [-/1 Points]

stiv31 [10]

multiply x times y divide by 6 on both sides and you got your answer

4 0

9 months ago

Does anyone how to solve this sum? It’s urgent

Galina-37 [17]

The required value for the sum is 9580.

$\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}$

<h3>What is simplification?</h3>

Simplification in mathematics to solve the given condition on its operators.

$\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}$

= $\frac{10000}{1.028^2} +68*\frac{1-\frac{1}{1.028^2} }{\frac{0.115}{4} } \\9451+68*\frac{1-0.94}{\frac{0.115}{4} } \\\\9451+68*\frac{0.054}{\frac{0.115}{4} } \\\\\\9451+3.72{\frac{4}{0.115} } \\\\\\9451+129\\$

= 9580

The required solution is given as 9580.

Learn more about simplification here:
brainly.com/question/9218183

#SPJ1

4 0

1 year ago

HELP! Find the missing value for the exponential function represented by the table below.

Mekhanik [1.2K]

B is your answer if you need me to explain why just ask me :) have a good day

3 0

3 years ago

Read 2 more answers

16 multiply 7/8 in simplest

denpristay [2]

Answer: 14

= 16 x (7/8)
= 8 goes into 16 2 times
= 2 x 7
= 14

5 0

2 years ago

PLEASE HELP ME!!!!!! Write the information in the table as ordered pairs. Graph the relationship from the table. ​

PLEASE HELP ME!!!!!! Write the information in the table as ordered pairs. Graph the relationship from the table.