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mojhsa [17]
3 years ago
9

Which expression is equivalent to [(14) (-1/4.89)] [_2]

Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0

Answer: (14)(-2/4.89)

i’m currently doing a test with the same expression as yours, i tried googling the answer which was no help. i eventually decided to work it out on my own and i came up with this answer

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Which is a correct first step for solving this equation?<br> - 32 + 2 - 52 - 7 = 4x + 2
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-8x - 5 = 4x + 2

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Solve - x/6 &gt;_ 3 <br> A <br> B <br> C <br> C
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Answer:

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-×/6>_3

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3 years ago
Which matrix can be multiplied to the left of a vector matrix to get a new vector matrix ?
oksano4ka [1.4K]

Answer:  The answer is (B).


Step-by-step explanation:  We are given four options and we are to select which matrix can be multiplied to the left of a vector matrix to get a new vector matrix. The order of a vector matrix is either n × 1  or  1 × n.

For (A): The order of the matrix is 2 × 1. If we multiply this matrix by a vector matrix of order 1 × 2, then the resulting matrix will be of order 2 × 2, which is not a vector matrix.

For (B): The order of the matrix is 3  × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 3 × 1, which is a new vector matrix.

For (C): The order of the matrix is 2  × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 2 × 1, which is a vector matrix of order same as before.

For (D): The order of the matrix is 1  × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 1 × 1, which is a not vector matrix.

Thus, the correct option is (B).

5 0
4 years ago
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Solve the equation: <img src="https://tex.z-dn.net/?f=5%5Ex%5E%28%5Ex%5E-%5E1%5E%29%3D1" id="TexFormula1" title="5^x^(^x^-^1^)=1
Tomtit [17]

<u>The concept:</u>

We are given the equation:

5^{x(x-1)} = 1

Which can be simplified as:

5^{x^{2} - x} = 1^{1}

Since any number to the power '0' is 1

x² - x must be equal to 0 for the given equation to be true

<u></u>

<u>Solving for x:</u>

x² - x = 0

x(x-1) = 0

now, we can divide both sides by either x OR x-1

So we will see what we get for either choice:

x = 0/(x-1)                           x-1 = 0/x

x = 0                                  x = 1

Hence, the value of x is either 0 or 1

7 0
3 years ago
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