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2 years ago

Evaluate r^2−s^2, when r=12 and s=5.

Mathematics

2 answers:

kramer2 years ago

5 0

Step-by-step explanation:

Given r = 12, s = 5,

${r}^{2} - {s}^{2} = {12}^{2} - {5}^{2} \\ = 144 - 25 \\ = 119$

abruzzese [7]2 years ago

3 0

Answer:

119

hope this helps

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Ima houseseller earns a 3% commision for selling a house. if he sells a house for $120000, what is his commision

Masja [62]

Commission is earning a certain percentage of the total sold price.

To figure this out we need to find what is 3% of $120,000

We can do this by multiplying 3% and $120,000

First let's change 3% into a decimal.

3% = 0.03

Now lets multiply.

0.03 x $120,000 = $3,600

So this person earned $3,600 in commission.

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2 years ago

Identify the slope and y-intercept of the line 8x+2y=6

sp2606 [1]

Answer:

Slope : -4

y-intercept : 3

Step-by-step explanation: Use the slope-intercept form y=mx+b to find the slope m and y-intercept b.

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3 years ago

Solve the equation<br><br>n/2 = -7

cluponka [151]

Answer: n = -14

Step-by-step explanation:

n/2 = -7

Multiply by 2 on each side to get the variable alone.

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4 0

3 years ago

Read 2 more answers

Determine whether each equation is True or False. In case you find a "False" equation, explain why is False.

elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) $\sqrt{32} = 2^{\frac{5}{2} }$

$2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ = \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}$

Thus, the equation is TRUE.

(2) $16^{\frac{3}{8} } = 8^2$

$16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64$

Thus, the equation is FALSE.

(3) $4^{\frac{1}{2} } = \sqrt[4]{64}$

$4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64} = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2} \times \sqrt{2} \times \sqrt{2} ) = 2\sqrt{2}$

Thus, the equation is FALSE.

(4) $2^8 = (\sqrt[3]{16} )^6$

$2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256$

Thus, the equation is TRUE.

(5) $(\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\$

$8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4$

Thus, the equation is FALSE.

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2 years ago

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marishachu [46]

Answer: The answer is D

Step-by-step explanation:

I used desmos graphing calculator! Look it up it really helps! Literally gives the answers. :)

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3 years ago