The relationship is not proportional because the boys and girls are in different grades and they are in different activities.
Answer: 
Step-by-step explanation:
We need to use the following formula to find the Midpoint "M":

Given the points (-5,13) and (6,4) can identify that:

The final step is to substitute values into the formula.
Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

An=-31+(n-1)-11 find the eleventh term
a11 = -31 + (-11) (11-1)
a11 = -31 +-11(10)
a11 =-31 +-110
a11 = -142
The problem uses the concept of Combination where there are number of members chosen from a group and there order is not important. Thus, the expression that would best describe the given above is 30C6 which means the combination of 30 taken 6. The numerical value for this is 593775.