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Anuta_ua [19.1K]

3 years ago

15

Of 11 available candidates for membership in a university committee, 6 are men and 5 are women. the committee is to consist of 4

persons. how many different selections of the committee are possible?

1 answer:

melomori [17]3 years ago

5 0

330 possible selections are possible

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What is the value of y2 – x2 when y = 6 and x = 5?

Papessa [141]

Answer:

y^2 - x^2 = 11

Step-by-step explanation:

y^2 - x^2 = ?

Substitute.

y = 6

x = 5

Becomes:

6^2 - 5^2 = ?

Solve.

6^2 = 6 x 6

6 x 6 = 36

5^2 = 5 x 5

5 x 5 = 25

36 - 25 = 11

8 0

2 years ago

If 1 mile equals 5280 feet and an escalator moves at a rate of 2 feet per second. At what rate does the escalator move in miles

Sever21 [200]

Ratio=2 ft/s
ratio=2 ft/s * (1 mile / 5280 ft)*(3600 s / 1 h)=1.36363636.. miles/h≈1.36 miles/h.

Answer: 1.36 miles/h

6 0

2 years ago

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Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!

vekshin1

Answer:

2. 3.913 kg (3 dp)

3. light cream

4. 240 CoffeeStops

5. 7 CoffeeStops per square mile

6. 2,861 cups of coffee each day

Step-by-step explanation:

Given:

Skim milk density at 20 °C = 1.033 kg/l
Light cream density at 20 °C = 1.012 kg/l
1 liter = 0.264 gallons

<u>Question 2</u>

$\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}$

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

<u>Question 3</u>

Given:

Volume of liquid = 9 liters
Mass of liquid = 9.108 kg

$\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}$

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

<u>Question 4</u>

Given:

15 CoffeeStops per 100,000 people
Population of Manhattan ≈ 1,602,000 people

$\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}$

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

<u>Question 5</u>

Given

Manhattan ≈ 34 square miles

$\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}$

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

<u>Question 6</u>

Given:

Each person buys 3 cups of coffee per week

$\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}$

$\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}$

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0

2 years ago

A.63<br> B.54<br> C.99<br> D.126

Neporo4naja [7]

Answer:

C

Step-by-step explanation:

Area = (8 + 14) x 1/2 x 9

Area = 22 x 1/2 x 9

Area = 11 x 9

Area = 99

<em>Hope that helps!</em>

<em>-Sabrina</em>

6 0

2 years ago

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Hi where is mc donalds?

Nikitich [7]

Maybe you can use your gps lololol

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2 years ago

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