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3 years ago

A set of four postcards costs $1.00. Single postcards cost $0.50. What is the least amount of money you

2 answers:

7 0

You would buy the set of four postcards 4 times. This would equal $4 for 12 postcards. Then you would have to buy 3 individual postcards. Those 3 postcards would be $1.50
$4+$1.50=$5.50

shepuryov [24]3 years ago

3 0

Answer: 3 Sets of the 4 post cards and 3 of the single post cart sets.

Step-by-step explanation:

You buy 3 of the 4 post card set becuase that is the most you can get of those to get under 15 post cards.

You would now have 12 postcards now you have to buy 3 of the single set to get to 15 cards

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True or false there is no line of symmetry in an isosceles trapezium. <br><br>

Mars2501 [29]

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3 years ago

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Simplify expression.<br> help me please

tatuchka [14]

Answer:

$\frac{-1}{x+3}$

Step-by-step explanation:

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2 years ago

The shadow of a telephone pole is 20 feet long. You measure the angle of elevation from the end of the shadow to the top of the

Aleks04 [339]

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Step-by-step explanation:

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3 years ago

What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2

NARA [144]

Given:

The inequalities are:

$-2$

$-2\leq x$

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

$-2$

$-2\leq x$

For $-2$ , the possible integer values are

$x=-1,0,1,2$ ...(i)

For $-2\leq x$ , the possible integer values are

$x=-2,-1,0,1$ ...(ii)

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3 years ago

If Aldo puts 400 into a savings account that paid an interest rate of 5.4 percent What was the total amount in his account at th

Ne4ueva [31]

Answer:

$\$421.60$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=1\ year\\ P=\$400\\ A=?\\r=5.4\%=5.4/100=0.054$

substitute in the formula above

$A=400(1+0.054*1)$

$A=400(1.054)$

$A=\$421.60$

Remember that Interest is equal to

$I=A-P$

$I=\$421.60-\$400=\$21.60$

5 0

3 years ago