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LuckyWell [14K]
3 years ago
9

A number, n, is divided by 4 and then subtracted from 5, resulting in 13. What is the value of n?

Mathematics
2 answers:
Bingel [31]3 years ago
8 0

Answer:

-6.8

Step-by-step explanation:

test-nav

borishaifa [10]3 years ago
3 0
Are you sure this question is right? there are no negatives? i’m pretty sure the answer is 72 but if i’m wrong, i’m sorry.
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Solve 3x-2/4 - 2x+5/3 = 1-x/6
Nadya [2.5K]

Answer:

Pasos para resolver una ecuación lineal

3x−2/4−2x+5/3=1−x/6

Multiplique ambos lados de la ecuación por 12, el mínimo común denominador de 4,3,6.

36x−3×2−24x+20=12−2x

Multiplica −3 y 2 para obtener −6.

36x−6−24x+20=12−2x

Combina 36x y −24x para obtener 12x.

12x−6+20=12−2x

Suma −6 y 20 para obtener 14.

12x+14=12−2x

Agrega 2x a ambos lados.

12x+14+2x=12

Combina 12x y 2x para obtener 14x.

14x+14=12

Resta 14 en los dos lados.

14x=12−14

Resta 14 de 12 para obtener −2.

14x=−2

Divide los dos lados por 14.

x=

14

−2

​

Reduzca la fracción  

14

−2

 a su mínima expresión extrayendo y anulando 2.

x=−

7

1

Step-by-step explanation:

7 0
2 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
3 years ago
Jon is allowed to play video games 5 hours throughout the week. so far this week , he has spent 2 5/6 hours playing games . how
Ivahew [28]
B: 2 and 1/6.

Tricky one if you rush through, its meant to SEEM complicated, like a lot of math questions.
8 0
3 years ago
curve before applying the theorem.)F(x, y) = y cos(x) − xy sin(x), xy + x cos(x), C is the triangle from (0, 0) to (0, 12) to (3
Serhud [2]

C has a clockwise orientation, so in order to use Green's theorem (which is probably the "theorem" mentioned here), we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=-\iint_D\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy\sin x)}{\partial y}\,\mathrm dx\,\mathrm dy

where D is the triangle region.

=\displaystyle\int_0^3\int_0^{12-4x}(\cos x-x\sin x)-(y+(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx

=\displaystyle-\int_0^3\int_0^{12-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-72}

4 0
3 years ago
Find the equation of this line. Simplify the fractions.<br> Please need help badly!!
Marina CMI [18]
Here you go!!! Hope it helps...

8 0
3 years ago
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