Answer:
The charge for admission is $6 and the charge for each ride is $2
Step-by-step explanation:
Let
x ----> the charge for admission
y ----> the charge for each ride
we have that
-----> equation A
-----> equation B
Solve the system by elimination
Subtract equation B from equation A
Find the value of x
substitute the value of y in any equation
therefore
The charge for admission is $6 and the charge for each ride is $2
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Answer:
9
Step-by-step explanation:
Given that the sample size is 45 blocks
Let number of red blocks in the bag to be x
Then the probability of chosing a red block will be x/45
Given that the probability of choosing a red block is 1/5 then you can form the expression;
x/45 = 1/5 ---------------find the value of x by performing cross multiplication
5x=45*1
5x/5=45/5
x=9
Answer
Julia put 9 red blocks in the bag.
Answer: x=2/3
Step-by-step explanation:
