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KengaRu [80]
2 years ago
5

What is (6x+4) - (4x+2)

Mathematics
1 answer:
Nana76 [90]2 years ago
4 0

Answer:

x = -1

Step-by-step explanation:

1. Simplifying

6x + 4 = 4x + 2

2. Reorder the terms

4 + 6x = 4x + 2 to 4 + 6x = 2 + 4x

3. Solving

4 + 6x = 2 + 4x

4. Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right. Then add '-4x' to each side of the equation.

4 + 6x + -4x = 2 + 4x + -4x

5. Combine like terms: 6x + -4x = 2x

4 + 2x = 2 + 4x + -4x

6. Combine like terms: 4x + -4x = 0

4 + 2x = 2 + 0

4 + 2x = 2

7. Add '-4' to each side of the equation.

4 + -4 + 2x = 2 + -4

8. Combine like terms: 4 + -4 = 0

0 + 2x = 2 + -4

2x = 2 + -4

9. Combine like terms: 2 + -4 = -2

2x = -2

10. Divide each side by '2'.

x = -1

11. Simplifying

x = -1

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Answer:

=44%of25

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Jelene is cutting a strip of yard that is 11/12 inch long into the pieces that are 2/12 inch long for a collage. How many comple
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3 years ago
The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.​
saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

\sf \:2 π r = r+ 74

\sf \: =   > 2 \times  \frac{22}{7}  \times r =  r \:  + 74

\sf \: =  >  \frac{44r}{7}  -r  = 74

\sf \:  =  > \frac{44r - 7r}{7}  = 74

\sf \: =  >  \frac{37r}{7}  = 74

\sf \: =  > r =  \frac{7 \times 74}{37}

\sf \: =  >  r = 14

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________________________________

3 0
2 years ago
Read 2 more answers
For what values of $x$ is it true that $x^2 - 5x - 4 \le 10$? Express your answer in interval notation.
dybincka [34]

Answer:

  x ∈ [-2, 7]

Step-by-step explanation:

The given equation ...

  x^2 -5x -4 ≤ 10

can be rewritten as ...

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and factored as ...

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Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.

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3 years ago
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