A hand of five cards is dealt from a normal pack of 52 cards, find the probability that there is no aces

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

4 0

3 years ago

What is the answer to this equation?

nika2105 [10]

Answer:

use photomath

Step-by-step explanation:

ur welcome

7 0

3 years ago

What is the volume of a cylinder with a height of 7.1 ft and a base with a diameter of 12.8 ft, to the nearest tenth of a cubic

Semenov [28]

Answer:

V=π(d

2)2h=π·(12.8

2)2·7.1≈913.62541ft³ Step-by-step explanation: because i said so

7 0

3 years ago

2a + 4b + c =5 x =-2 a - 4b = -6 y=1

cricket20 [7]

There is no solution ,a+c=-10;b-c=15;a-2b+c=-5 No solution System of Linear Equations entered : [1] 2a+c=-10 [2] b-c=15 [3] a-2b+c=-5 Equations Simplified or Rearranged : [1] 2a + c = -10 [2] - c + b = 15 [3] a + c - 2b = -5 Solve by Substitution :

// Solve equation [3] for the variable c

[3] c = -a + 2b - 5

// Plug this in for variable c in equation [1]

[1] 2a + (-a +2?-5) = -10 [1] a = -5

// Plug this in for variable c in equation [2]

[2] - (-? +2b-5) + b = 15 [2] - b = 10

// Solve equation [2] for the variable ?

[2] ? = b + 10

// Plug this in for variable ? in equation [1]

[1] (? +10) = -5 [1] 0 = -15 => NO solution No solution

3 0

3 years ago

What is the defination of the focus when referring to a parabola?

Len [333]

Answer:

Focus of a Parabola. A parabola is set of all points in a plane which are an equal distance away from a given point and given line. The point is called the focus of the parabola and the line is called the directrix. The focus lies on the axis of symmetry of the parabola.

Step-by-step explanation:

6 0

3 years ago