A hand of five cards is dealt from a normal pack of 52 cards, find the probability that there is no aces

Mathematics

1 answer:

stich3 [128]3 years ago

4 0

TOTAL OUTCOMES =52-5=47

FAVOURABLE OUTCOME = 47-4=43

P[E]=43/47

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PLZ HELP ASAP SIMILARITY

PIT_PIT [208]

LY = 5.2 , TY = 3.9
Δ LTN is a right triangle , ∠T = 90° , TY⊥LN
∴ TY² = LY * YN
∴ 3.9² = 5.2 * YN
∴ YN = 3.9²/5.2 = 2.925

∴ LN = LY + YN = 5.2 + 2.925 = 8.125

Δ LYT is a right triangle , ∠Y = 90°
LT² = LY² + YT² = 5.2² + 3.9² = 42.25
∴ LT = √42.25 = 6.5

Δ NYT is a right triangle , ∠Y = 90°
NT² = NY² + YT² = 2.925² + 3.9² = 23.765
∴ NT = √23.765 = 4.875

The preimeter of the rectangle LINT = 2 * (LT + TN)
                                                          = 2 * ( 6.5 + 4.875 )
                                                          = 2 * 11.375
                                                          = 22.75

7 0

3 years ago

Punctele A,B si C sunt coliniare in aceasta ordine.Aflati lungimea segmentului:a)AB,daca AC=20cm,BC=0,12dm

Strike441 [17]

Answer:

The length of the segment AB is 18.8 cm or 1.88 dm

Step-by-step explanation:

<u><em>The question in English is</em></u>

Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm

we have that

$AC=AB+BC$ ----> by Addition segment postulate