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3 years ago

7

Name the property illustrated be each statement. (3x+2)-5=(3x+2)-5

1 answer:

Evgesh-ka [11]3 years ago

8 0

The associative property states that we can add numbers in any way we want to still get the same sum, so the parenthesis here can essentially be tossed out to get 3x+2-5=3x-3. However, make sure, for example, that you don't add x and 1 together in 3(x)+1 as you still have to multiply the x with 3 before adding the 1 according to PEMDAS

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Can someone tell me the answer to me pls I have to be done in 20 minutes

Feliz [49]

Answer:

x = 9.25

Step-by-step explanation:

It is given that ABC is an isosceles triangle.

m∠A = 43° and m∠C = (6x+13)°

We need to find the value of x.

The sum of a triangle is equal to 180°.

∠A is the vertex angle. For a triangle sum of angle of triangle is equal to 180°

∠A+∠B +∠C=180

43+∠B+(6x+13)°=180

6x+∠B+56=180

6x+∠B = 124

∠B =124-6x

For an isosceles triangle,

∠B = ∠C

124-6x = (6x+13)

124-13 = 6x+6x

111 = 12x

x = 9.25

So, the value of x is 9.25.

7 0

3 years ago

Factor: 10x^2-15x=0 ?

e-lub [12.9K]

Like every quadratic equation

$ax^2+bx+c=0$

where $c=0$

$ax^2+bx=0$

we can factor out $x$

$x(ax+b)=0$

And find the two solutions

$x=0,\quad x=-\dfrac{b}{a}$

In this case, the solutions are

$x=0,\quad x=\dfrac{3}{2}$

If you know that $x_1,\ x_2$ are the solutions to the quadratic equation

$ax^2+bx+c=0$

then you can factor the poynomial as

$a(x-x_1)(x-x_2)$

So, in this case, you have

$10x^2-15x = 10(x-0)\left(x-\dfrac{3}{2}\right)=10x\left(x-\dfrac{3}{2}\right)$

8 0

4 years ago

Solve for x<br> x²+11²+(x+5)²

BlackZzzverrR [31]

Answer:

2 • (x2 + 5x + 73)

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant

Step-2 : Find two factors of 73 whose sum equals the coefficient of the middle term, which is 5

Pulling out like terms/factors

Trying to factor by splitting the middle term

Answer: 2 • (x2 + 5x + 73)

Hope this helps.

4 0

3 years ago

Read 2 more answers

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

Which of the following is an equation of the line that has a slope of 1/3 and passes through the point (-6, 2)?

sineoko [7]

Answer:

y-2=1/3(x+6)

Step-by-step explanation:

y-2=1/3(x-(-6))

y-2=1/3(x+6)

3 0

3 years ago