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3 years ago

Find surface area of this regular pyramid

Mathematics

1 answer:

liq [111]3 years ago

7 0

Answer:

189 ft²

Step-by-step explanation:

Here is the formula...

1/2 * 6 * 36 + 81

Hope this helps

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a recipe calls 1 2/3 cups of brown sugar for the granola bars and 1 q/3 cups of brown sugar for the topping. Dara has 3 1-4 cups

sp2606 [1]

Answer:

yes, she does have enough

Step-by-step explanation:

3 1/4 - 1 1/3 - 1 2/3

=1/4

4 0

3 years ago

What is the area of a circle whose diameter is 64

navik [9.2K]

Answer:

A ≈ 3215.36

Step-by-step explanation:

A = πr²

Radius - D/2

Radius - 64/2 → 32

A = 3.14(32)²

A = 3215.36

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

3 0

3 years ago

I don’t understand any of this

Nookie1986 [14]

Answer:

1. 1244.07

2. 653.45

3. 706.86

4. 141.37

5. 2309.07

6. 402.12

7. 863.94

8. 2001.19

9. 197.92

Step-by-step explanation:

6 0

3 years ago

An equation is graphed below. How many solutions does the equation have?

Dimas [21]

One as it intersects only on the Y axis

6 0

3 years ago