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Eddi Din [679]
2 years ago
7

Please help. Will give brainliest to correct answer.

Mathematics
2 answers:
mr Goodwill [35]2 years ago
3 0

Answer:

Step-by-step explanation:

B

beks73 [17]2 years ago
3 0

Answer:

the second choice

Step-by-step explanation:

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What is the value of the missing angle?a, 720b, 120c, 128d, 138
Zigmanuir [339]
The sum of all the interior angles in a hexagon is 720°, so if you add up all the angles and then take them away from 720, you'll get your answer:
152 + 85 = 237
237 + 85 = 322
322 + 125 = 447
447 + 135 = 582
So 720 - 582 = 138°, which is your answer. I hope this helps!
3 0
3 years ago
Which expression is equivalent to 15n – 20?
Semenov [28]

The only thing you can do with this expression is to factor a 5 out of the two terms: we have

15n-20 = 5(3n-4)

3 0
3 years ago
Read 2 more answers
What are some solutions of the question 3x^2-5x+2=0?
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

3x²-5x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

(x-1)(3x-2)=0

either x-1=0 which gives x=1

or 3x-2=0

x=2/3

7 0
3 years ago
Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is
nadya68 [22]

I'll leave the computation via R to you. The W_i are distributed uniformly on the intervals [0,10i], so that

f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}

each with mean/expectation

E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i

and variance

\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2

We have

E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3

so that

\mathrm{Var}[W_i]=\dfrac{25i^2}3

Now,

E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30

and

\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]

\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2

We have

(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)

E[(W_1+W_2+W_3)^2]

=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])

because W_i and W_j are independent when i\neq j, and so

E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3

giving a variance of

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3

and so the standard deviation is \sqrt{\dfrac{350}3}\approx\boxed{116.67}

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

\mathrm{Var}[W_1+W_2+W_3]

=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])

and since the W_i are independent, each covariance is 0. Then

\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3

and take the square root to get the standard deviation.

8 0
3 years ago
Luis works 45 hours and earns 10 an hour. How much money would he earn in 3 weeks.
daser333 [38]

Answer: $1,350

Step-by-step explanation:

45 hours x 10 dollars/hour = 45x10 dollars = 450 dollars/week

450 dollars/week x 3 weeks = 450x3 dollars = 1350 dollars

3 0
3 years ago
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