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tamaranim1 [39]
3 years ago
12

What is the average rate of change for ƒ(x) = −2x + 70 over the interval 2 ≤ x ≤ 6?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

The average rate of change is -2

Step-by-step explanation:

we know that

To find out the average rate of change, we divide the change in the output value by the change in the input value.

In a linear function the average rate of change is a constant and is equal to the slope of the function

The linear function in slope intercept form is equal to

f(x)=mx+b

where

m is the slope or unit rate of the linear function

b is the y-intercept or initial value of the linear function

In this problem we have

f(x)=-2x+70

so

m=-2\\b=70

therefore

The average rate of change is -2

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Use the substitution method to solve the system of equations. Enter your
Mazyrski [523]

Answer:

Here ya go

Step-by-step explanation:

Examples: 1+2, 1/3+1/4, 2^3 * 2^2

(x+1)(x+2) (Simplify Example), 2x^2+2y a x=5, y=3 (Evaluate Example)

y=x^2+1 (Graph Example), 4x+2=2(x+6) (Solve Example)

3 0
3 years ago
Use substitution to solve the system.<br> -5x + 3y = 19<br> x = 3y - 11
telo118 [61]

Answer:

x = -2

y = 3

Step-by-step explanation:

-5x + 3y = 19

x = 3y - 11

-5x + 3y = 19

-5(3y - 11) + 3y = 19

-15y + 55 + 3y = 19

-15y + 3y + 55 = 19

-12y + 55 = 19

-12y = 19 - 55

-12y = -36

y = -36/-12

<u>y = 3</u>

x = 3y - 11

x = 3(3) - 11

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<u>x = -2</u>

5 0
3 years ago
Diego made a castle with small building blocks. He used an even number of blocks. The number of blocks is between 700 and 800. T
vovikov84 [41]

Answer:

The two numbers are 476 and  284

Step-by-step explanation:

Given:

He used an even number of blocks

The number of blocks is between 700 and 800

The number of blocks is the sum of two

To Find :

Two number = ?

Solution:

The sum of  an odd number and an even number id always odd. So  423 can be eliminated

So two numbers must be any of the 4 remaining options

Its also given that the number lies between 700 and 800. So the sum should be greater than 700 and lesser than 800

by trial and error method

352+476 = 828 ( greater than 700 but greater than 800, condition fails)

352+326 = 678  ( lesser than 700 but lesser than 800, condition fails)

352+284 = 636 ( lesser than 700 but lesser than 800, condition fails)

476+326 = 802 ( greater than 700 but greater than 800, condition fails)

476+284 = 760 (  greater than 700 and lesser than 800)

5 0
3 years ago
a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti
defon

The school net ball team drew 2 matches. The team won \frac{5}{8} of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew \frac{1}{8} of the total played

Let the total number of matches played be "n"

Number of matches drawn = \frac{1}{8} of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}

Taking "n" as common from left hand side,

\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}

So, they played 16 matches in total

Number of matches drawn = \frac{1}{8} of n = \frac{1}{8} \times 16 = 2\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}

\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }

3 0
3 years ago
Find the measure of angle ABD
Brut [27]

Answer:

137

Step-by-step explanation:

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now we know <ABC = 118 and

the measure of central angle <CBD is equal to measure of the arc it sees so it's = 105

we are asked to find the  m<ABD

118 + 105 + <ABD = 360 add like terms

223 + <ABD = 360 subtract 223 from both sides

m<ABD = 137

5 0
2 years ago
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