Standard quadratic equation .. y = a x^2 + b x + c
<span>parabola 'a' not equal to zero </span>
<span>a<0 parabola opens downward </span>
<span>a>0 parabola opens upward </span>
<span>when |a| >>0 the parabola is narrower </span>
<span>when |a| is close to zero , the parabola is flatter </span>
<span>when the constant is varied it only effects the vertical position of the parabola , the shape remains the same</span>
Answer: B and D are correct.
Step-by-step explanation:
A is wrong because they will eventually intersect (the arrows show that the line continues on).
B is correct; that is where they will intersect.
C is wrong because they only intersect at one point, and that's where the solution is.
D is correct because they intersect once and have only one solution.
Answer:
x > -11
Step-by-step explanation:
<u>Step 1: Subtract 6 from both sides</u>
-4x + 6 - 6 < 50 - 6
-4x < 44
<u>Step 2: Divide both sides by -4</u>
-4x / -4 < 44 / -4
If you divide by a negative number, you flip the sign.
<em>x > -11</em>
<em />
Answer: x > -11
