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2 years ago

A dress is $40 and is marked down 25% what is the discount and sales price of the dress?

Mathematics

2 answers:

marta [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Discount $40 x 25% = $10

Sales price $40-$10 = $30

sp2606 [1]2 years ago

4 0

Answer:

Discount: $10

Price: $30

Step-by-step explanation:

There's a few different ways to approach this but here's the way i'd use...

25% can also be expressed as 1/4. This means that we can divide the price of the dress by 4 to find the discount.

40 / 4 = 10.

The discount is $10

To find the sales price of the dress, we just need to subtract the discount.

40 - 10 = 30.

The dress costs $30

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Nancy started the year with 400$ in the bank and is saving 10$ a week. Shane started with 700$ and is spending 20$ a week. When

umka21 [38]

They will both have the same amount in the bank after 10 weeks

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the solution to the system?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, we have

<u>Nancy</u>

Initial = 400

Rate = 10

So, the equation is

y = 400 + 10x

Initial = 700

Spending = 20

So, the equation is

y = 700 - 20x

When they both have the same amount of money in the bank, we have

700 - 20x = 400 + 10x

Evaluate the like terms

30x = 300

Divide by 30

x = 10

Hence, they will both have the same amount in the bank after 10 weeks

Read more about linear equations at:

brainly.com/question/1884491

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5 0

1 year ago

Please answer the question in the picture

rosijanka [135]

answer:

(5x-1)(x-3)

explanation:

→ 5x² - 16x +3

→ 5x² -15x - x +3

→ 5x(x-3)-1(x-3)

→ (5x-1)(x-3)

3 0

2 years ago

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Yanka [14]

The answer is D

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3 years ago

An open metal tank of square base has a volume of 123 m^3

snow_lady [41]

Answer:

a) h = 123/x^2

b) S = x^2 +492/x

c) x ≈ 6.27

d) S'' = 6; area is a minimum (Y)

e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

123 = x^2·h

h = 123/x^2

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

$S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}$

c) The derivative of the area with respect to x is ...

$S'=2x-\dfrac{492}{x^2}$

When this is zero, area is at an extreme.

$0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583$

d) The second derivative is ...

$S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6$

This is positive, so the value of x found represents a minimum of the area function.

e) The minimum area is ...

$S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78$

The minimum area of metal used is about 117.78 m².

3 0

2 years ago

If you can answer this and show your work ill give brainly

Arlecino [84]

Answer:

First answer is 127 and second answer is 15

8 0

2 years ago

Read 2 more answers