The fewest number of hours from the graph is 73 hours.
<h3>Equation</h3>
Equation is an expression used to show the relationship between two or more numbers and variables.
Let x represent the number of $10 course and y represent the number of $15 course.
Her goal is to save at least $1000, hence:
Also:
The fewest number is (20, 53)
The fewest number of hours from the graph is 73 hours.
Find out more on equation at: brainly.com/question/2972832
Answer:
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Explanation:
Answer:
Change in M1 $400
Changd in M2 $0
Explanation:
The money which is been held by individuals in savings accounts is part of the M2 money supply, but its not part ofthe M1 money supply.
Hence when Jane withdraws $400 cash from her savings account,the M1 money supply will increases by $400. However, the M2 money supply does not tend to change reason been that the M1 money supply is included as part of the M2 money
Change in M1 $400
Changd in M2 $0
Answer:
$4,775,565.49
Explanation:
The computation of the selling price of the bond is shown below:
Particulars Amount PV factor 6% Present value
Semi-annual interest $216,209 19.60044 $4,237,791.53
Principal $3,088,700 0.174110131 $537,773.96
Total $4,775,565.49
Working notes
Semi-annual interest $216,209 = $3,088,700 × 14% × 6 ÷ 12
PV factor 3%:
Semi-annual interest 13.76483115 = {(1 - (1.06)^-30) ÷ 0.06
}
Principal 0.174110131 = {1 ÷ 1.03^30}
Answer:
1.41 Approx
Explanation:
The computation of the beta for the stock T is shown below:
Beta of portfolio = Respective betas × Respective investment weights
1.30 = (0.14 × 0.81) + (0.5 × 1.36) + (0.36 × beta of the Stock T)
1.30 =0.7934 + (0.36 × beta of the Stock T)
beta of the Stock T = (1.3 - 0.7934) ÷ 0.36
= 1.41 Approx
We simply multiplied the beta of each stock with its investment weights order to calculate the beta of the stock T as portfolio beta is given