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dimulka [17.4K]
3 years ago
5

Two consecutive odd negative integers have a product of 483, find the integers ...?

Mathematics
2 answers:
kondaur [170]3 years ago
7 0
Negative 21 and Negative 23 are the two integers you are looking for. Two negatives make a positive and the are both consecutive odd integers that = 483 when multiplied.
irinina [24]3 years ago
3 0
In order to find this you need to assume that they are declared as X and as X + 2. This makes the formula for calculating it x (x+2)=483, and this, based on the formulas for calculation, equals

 x^2+2x-83=0

From this we can see that a negative X is -23, which when +2 is added results in -21.

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I hope that helps (:

1. The entire fraction is negative if the numerator or denominator are negative.

if both parts of the fraction were negative, the entire fraction would be positive (- / - = +)

2. Of course, although most teachers ask you to put the negative sign in the fraction as a whole (before the fraction line) or in the numerator. never leave a fraction with two signs. in this case, if it has two signs and they are different, the whole fraction is NEGATIVE

3) No. the whole fraction is POSITIVE only if both the numerator and the denominator have the same sign, + + or - -

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3 years ago
How do I graph a rational function with a y intercept. Example 3x^2-1/2x+4 +1
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4 years ago
How to solve in long division 82.14 divided by 6.
omeli [17]

Answer: 13.69

Step-by-step explanation:

82.14/6=

Multiply 82.14 by 100 to make it a whole number; since you're modifying the number, you must also multiply 6 by 100 in order to keep it balanced.

82.14*100/6*100

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---------------------------------------------------------------------

Let's begin.

8214/600=13.69

600

----------

221'4

1800

--------

414'0

3600

--------------

540'0

5400

-----------

    -

7 0
3 years ago
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