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3 years ago

HELP HELP HELP HELP HELP PLSSSSSSSS

Mathematics

2 answers:

nata0808 [166]3 years ago

7 0

Answer:

Step-by-step explanation:

valentinak56 [21]3 years ago

6 0

Answer:

I have no idea. Umm maybe ask your mom. Or dad do either of them know math?

U could try to email your teacher.

Step-by-step explanation:

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Jill wrote the number 40. if her rule is add 7 what is the fourth number in jills pattern

Sedbober [7]

1) 40+7=47
2) 47+7= 54
3) 54+7 = 61
4) 61+7 = 68
The answer is 68.

6 0

3 years ago

Find the area of the circle.

juin [17]

Answer:

See Explanation Below

Step-by-step explanation:

Your question isn't clear; However, I'll solve in two ways

1. Diameter = 14 cm

2. Radius = 14 cm

<em>When Diameter = 14 cm</em>

Given

$Area = \pi r^2$

$Diameter = 14cm$

Required

Calculate the area of the circle

First, the radius has to be solved;

$Radius = \frac{1}{2} Diameter$

$Radius = \frac{1}{2} * 14cm$

$Radius = 7cm$

Using the given formula;

The area is as follows

$Area = \pi r^2$

$Area = 3.14 * 7^2$

$Area = 3.14 * 49$

$Area = 153.86cm^2$

<em>When Radius = 14 cm</em>

Given

$Area = \pi r^2$

$Radius = 14cm$

Required

Calculate the area of the circle

Using the given formula;

The area is as follows

$Area = \pi r^2$

$Area = 3.14 * 14^2$

$Area = 3.14 * 196$

$Area = 615.44cm^2$

7 0

3 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$